Add -1/3 plus -2/5. And then multiple that fraction by what ever is in the () and then I think that's it
Answer: 14 units
Step-by-step explanation:
Answer:
A. When Katina has $280 in her bank account, 4 months have passed. Plug 4 months into Malorie's bank account equation:
a = 50(4) + 100
a = 200 + 100
a = $300
B. Malorie's bank account changes at a greater rate. Katina's bank account amount increases by $20 each month, whereas Malorie's bank account increases by $50.
Ex: month 5
Katina has 300, 20 more than the previous month.
Malorie has 350, 50 more than the previous month
Answer:
a = 8
b ≠ 18
Step-by-step explanation:
y = 4x - 7
2y = ax + b
For there to be no solution, the lines (if graphed) should be parallel meaning that their slopes are equal but the y-intercepts are different
y = mx +b is the equation of a line where m is the slope and b is the y-intercept
Multiply the first equation by 2
2y = 8x - 14
2y = ax + b
So a has to equal 8
b can be anything except 14 (otherwise the lines would be the same)
B.) Hibiscus Street
The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept
So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.
Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
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A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.
C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.
D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.
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