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Novay_Z [31]
3 years ago
7

Bethany says that 3x+6+x and 3(x+2) and equivalent expressions. She used substitution to support her answer. Explain what Bethan

y did wrong
Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

She forgot about the final x at the end, because the first expression is 3x+6+x, and the second one is 3(x+2). The second one expands to 3x+6, but it doesn't have the final term at the end.

Also, 3 is not really a factor of x (technically it could be because x in unknown, but in terms of like terms and stuff it isn't) so you can't take a 3 out of x (unless you leave it as 1/3x I guess).

Anyway, yeah she forgot about the final x and therefore the factor she took out is incorrect anyway. She also could've simplified the first expression so that it became 4x + 6

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Please refer to the attachment

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kotegsom [21]

Answer:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

Step-by-step explanation:

Given the table

x   1      3      5      7

y   5      9      13     17

E)

It is clear that there is a CONSTANT CHANGE in the x and y values of the graph.

THE CONSTANT CHANGE IN X VALUES

i.e. 3-1=2, 5-3=2, 7-5=2

THE CONSTANT CHANGE IN Y VALUES

i.e. 9-5 = 4, 13 - 9 = 4, 17 - 13 = 4

Thus, the given table represents the linear function is TRUE

B)

It is clear that the value of y increase as the value of x increases.

Thus, the statement ''the value of y decreases as the value of x increases'' is FALSE!

D)

We know that the slop-intercept form of the line equation is

y = mx+b

where m is the slope and b is the y-intercept.

Determining the equation

Taking two points

(1, 5)

(3, 9)

Finding the slope between (1, 5) and (3, 9)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [9 - 5] / [3 - 1]

               = 4 / 2  

               = 2

Thus, the slope of the line = m = 2

now substituting m = 2 and the point (1, 5) to determine the y-intercept

y = mx+b

5 = 2(1) + b

b = 5-2

b = 3

Thus, the value of y-intercept b = 3

substituting b = 3 and m = 2 in the slope-intercept form

y = mx+b

y = 2x+3

Therefore, the equation for the line function is y = 2x+3 is TRUE

A)

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

We already know that the y-intercept b = 3

It means the y-intercept modeled is (0, 3)

Therefore, the statement of the function modeled is (0, 3) is TRUE.

C)

We have already got the equation

y = 2x+3

substituting x = 8

y = 2(8)+3

y = 10+3

y = 13

so at x = 8, the value of y = 13

Therefore, the statement that the ''On a graph of the function when x = 8, the value of y will be 2'' is FALSE!

Conclusion:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

3 0
3 years ago
Please help!! I will give brainliest thank you!!
mamaluj [8]

\bold{\huge{\red{\underline{Solution}}}}

\bold{\underline{ Given :- }}

  • We have given two figures that rectangle and parallelogram
  • The base and height of parallelogram is 7ft and 5ft
  • The length and breath of rectangle is 3ft and 1ft .

\bold{\underline{ To \: Find :- }}

  • We have to find the area of shaded part?

\bold{\underline{ Let's \: Begin :- }}

Firstly, we will calculate the area of parallelogram then area of rectangle after that we will subtract the area of rectangle from the area of parallelogram then we got the area of shaded part.

\sf{\pink{Area \:of\: parallelogram = Base * height }}

\sf { = 7 × 5 }

\sf { = 35ft }

\sf{ Thus,  \:The \:area\: of \:parallelogram\: is \:35ft}

\sf{\underline{ Now}}

\sf{\blue{Area\: of\: rectangle = L × B }}

\sf{ = 3 × 1 }

\sf{ = 3ft}

\sf{Thus, \:The\: Area\: of \:rectangle\: is\: 3ft}

\sf{\underline{ Now}}

\sf{ Total\: area \:of \:shaded\: part }

\sf{ Area\: of\: parallelogram - Area\: of\: rectangle }

\sf{ = 35 - 3}

\sf{ = 32 ft}

\bold{\pink{Hence, \: Area\: of \:shaded\: part \:is\: 32ft}}

8 0
2 years ago
Find a polynomial of degree 3 that has the following zeros -4, 0, 3
Tatiana [17]
Look at the attachment

4 0
3 years ago
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