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3 years ago

Which of these points lies on the line described by the equation below y-3=5(x-9)

Mathematics

2 answers:

ladessa [460]3 years ago

5 0

Answer:

(9,3)

Step-by-step explanation:

We have been given an equation of a line $y-3=5(x-9)$ and we are asked to find the point that lies on our given line.

Since we know that point-slope form equation of a line is: $(y-y_1)=m(x-x_1)$ , where,

m = The slope of the line.

$(x_1,y_1)$ = The coordinates of given point on the line.

Since our given equation is in point-slope form, so x-coordinate of our given point is 9 and y-coordinate of our given point is 3.

Therefore, point (9,3) lies on the line described by our given equation.

s344n2d4d5 [400]3 years ago

3 0

(9,3) is the answer because in point slope form what x and y and subtrating from is the point it lies on

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ddd [48]

Answer:

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Step-by-step explanation:

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Thus:

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3 years ago

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GuDViN [60]

Answer:

You must order the operations in the way that it unfolds in the explanation;:

Step-by-step explanation:

(25 x 9) +75 + 50+ 9 x ( 3 + 1)

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(25 x 9) =225 +75= 300+50 = 350+9 = 359 x (3+1 )

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Hatshy [7]

Answer:

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Step-by-step explanation:

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3 years ago

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The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre

Rasek [7]

Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

$f(x)=b+mx$

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

At 104 chirps per minute, the temperature is 63 ºF.

At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

Find the slope:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}$

Find the equation:

$81=\frac{1}{4}\cdot 104+b$

Solving for b

$b=81-\frac{1}{4} (176)=37$

Therefore, the linear function is

$y=\frac{1}{4} \cdot x+37$

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

$y=\frac{1}{4} \cdot (124)+37=68$

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RoseWind [281]

Answer:

I believe the answer is D

Step-by-step explanation:

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Hope this helps!

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