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Simora [160]
3 years ago
12

How do u work.like do u use this

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

you ask a question and someone will answer it just make sure to include all the information necessary so people are able to help u out properly

Step-by-step explanation:


You might be interested in
What is the degree of the monomial?<br> 3.25 + 2x2 - y+3
disa [49]

Answer:

5

Step-by-step explanation:

The degree is just the number with the highest power. In this case, it is 3^5. Therefore, 5 is the degree.

If this helps please mark as brainliest

8 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Sav [38]
I think this is y = 2/1x+1
4 0
3 years ago
Find the volume of a pyramid with a square base, where the side length of the base is
nlexa [21]

Answer:

336.8 cubic meter or 336.8m³

Step-by-step explanation:

In other to solve the above question we would be using the volume of a square based pyramid.

The formula for the volume of a square based pyramid is

1/3a²h

In the above question we are given the following values as:

Side length of the base = a = 11.1 m

Height of the pyramid = h = 8.2m

Volume of the square based pyramid = 1/3 × 11.1² × 8.2

= 336.774 cubic meter or 336.774 m³

Approximately to the nearest tenth = 336.8 cubic meter or 336.8m³

8 0
3 years ago
BRAINLIEST ANSWER
Alex

Question asked: if a number has an absolute value equal to 9,that number could be ____?

My answer: it would be C. -9 or 9


4 0
3 years ago
Read 2 more answers
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
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