Hey!

A function in slope-intercept form would look like y=mx+b; with the x and y values on the opposites of the equation.

A function in standard form would look like ax+by=c; with the x and y values on the same side of the equation.

Hope this helps!

3 0

3 years ago

Read 2 more answers

What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)

Xelga [282]

$(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}$

5 0

3 years ago

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What is the solution to the trigonometric inequality 2sin(x)+3>sin^2(x) over the interval 0<=x<=2pi radians?

densk [106]

Answer:

A 2-column table with 6 rows. Column 1 is labeled x with entries 1.99, 1.999, 1.9999, 2.0001, 2.001, 2.01. Column 2 is labeled f (x) with entries 0.505, negative 0.827, 0.306, negative 0.306, 0.827, negative 0.506.

Find Limit of f (x) as x approaches 2 f(x), if it exists.

0.3

DNE

Step-by-step explanation:

5 0

2 years ago

Since the area under the normal curve within two standard deviations of the mean is 0.95, the area under the normal curve that c

alukav5142 [94]

Answer:

$X \sim N (\mu ,\sigma)$

And for this case we know this condition:

$P(\mu-2\sigma$

By the complement rule we know that:

$P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05$

But since the distribution is symmetrical we know that:

$P(X\mu +2\sigma) = 0.025$

So then the statement for this case is FALSE.

b. False

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

For this case if we define the random variable of interest X and we know that this random variable follows a normal distribution:

$X \sim N (\mu ,\sigma)$

And for this case we know this condition:

$P(\mu-2\sigma$

By the complement rule we know that:

$P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05$

But since the distribution is symmetrical we know that:

$P(X\mu +2\sigma) = 0.025$

So then the statement for this case is FALSE.

b. False

5 0

3 years ago