Answer:
True
Step-by-step explanation:
For example:
HCF of 2 and 3 is 1
Answer:
(a)
The probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
Step-by-step explanation:
(a)
Case 1
Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

Case 2
Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

Therefore the probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
4 divided by 3 = a whole and 3 repeated more than 4 times
(to use the number 4)
:D
Answer:
2 
Step-by-step explanation:
Change the mixed numbers to improper fractions
(
-
) +
← the LCM of 2 and 3 is 6
=
-
+ 
=
-
+ 
=
+ 
= 
= 
= 2 
6 one-dollars = $6 15 five-dollars = $75 9 ten-dollars = $90 Add them
all up to get $171, so that is correct. Add the number of one-dollar
bills and the number of ten-dollar bills together. 6 + 9 = 15, which is
the number of five-dollar bills, so that is correct as well. Add all the
numbers of bills together, 6 + 9 + 15 = 15 + 15 = 30.