Ask question

Ask question

All categories

3 years ago

8

PLS HELP I AM TIMED 10 POINTS You are told that a triangle has two equal angles. What type of triangle could it be? Check all of

the boxes that apply. acute equilateral isosceles obtuse right scalene

1 answer:

riadik2000 [5.3K]3 years ago

4 0

Answer:

Obtuse, right, isoceles, acute

Step-by-step explanation:

You might be interested in

Help!................

Ber [7]

40+20+5+10+30+10+5+20=144
40-20-5-10-30-10-5-20=-60
144-60=84
so 84 is ur answer

4 0

4 years ago

Please help me I need help!!!!

Lelu [443]

The answer to your question is C.

6 0

4 years ago

What are the y and x intercepts of y=3(x-6)²-9 and y=-2(x+5)²+3 .. Thanks

JulsSmile [24]

1.
$y=3(x-6)^2-9 \\ \\
\hbox{x-intercept - y=0} \\
0=3(x-6)^2-9 \\
9=3(x-6)^2 \ \ \ |\div 3 \\
3=(x-6)^2 \\
\sqrt{3}=\sqrt{(x-6)^2} \\
\pm \sqrt{3}=x-6 \\
\pm \sqrt{3}+6=x \\
x=6+\sqrt{3} \ \lor \ x=6-\sqrt{3}} \\ \\
\hbox{y-intercept - x=0} \\
y=3(0-6)^2-9 \\
y=3 \times (-6)^2-9 \\
y=3 \times 36-9 \\
y=108-9 \\
y=99 \\ \\
\boxed{\hbox{x-intercepts: } 6+\sqrt{3} \hbox{ and } 6-\sqrt{3}} \\
\boxed{\hbox{y-intercept: } 99}$

2.
$y=-2(x+5)^2+3 \\ \\
\hbox{x-intercept - y=0} \\
0=-2(x+5)^2+3 \\
-3=-2(x+5)^2 \ \ \ |\div (-2) \\
\frac{3}{2}=(x+5)^2 \\
\sqrt{\frac{3}{2}}=\sqrt{(x+5)^2} \\
\pm \sqrt{\frac{3}{2}}=x+5 \\
\pm \sqrt{\frac{3}{2}}-5=x \\
x=\sqrt{\frac{3}{2}}-5 \ \lor \ x=-\sqrt{\frac{3}{2}}-5 \\ \\
\hbox{y-intercept - x=0} \\
y=-2(0+5)^2+3 \\
y=-2 \times 5^2 +3 \\
y=-2 \times 25+3 \\
y=-50+3 \\
y=-47 \\ \\ \boxed{\hbox{x-intercepts: } \sqrt{\frac{3}{2}}-5 \hbox{ and } -\sqrt{\frac{3}{2}}-5} \\ \boxed{\hbox{y-intercept: } -47}$

7 0

3 years ago

GarryVolchara [31]

Answer:

Lines f and g are parallel.

Angle 2 is congruent to angle 6.

Angle 2 and angle 5 are supplementary

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

13 students are going on a field trip4 students can ride in each carHow many cars will they need for the field trip?

inessss [21]

Answer:

4

Step-by-step explanation:

1. Divide total number of students by number of students per car (use remainder rather than decimal)

13/4 = 3, remainder 1

In this case, round up because no student can be left behind. 4 cars will be used.

7 0

4 years ago

Read 2 more answers