Ask question

Ask question

All categories

3 years ago

8

PLS HELP I AM TIMED 10 POINTS You are told that a triangle has two equal angles. What type of triangle could it be? Check all of

the boxes that apply. acute equilateral isosceles obtuse right scalene

1 answer:

riadik2000 [5.3K]3 years ago

4 0

Answer:

Obtuse, right, isoceles, acute

Step-by-step explanation:

You might be interested in

which function below represents exponential decay?ƒ(x) = 0.5(2)xƒ(x) = 4(0.25)xƒ(x) = 2(1.3)xƒ(x) = (-3)x

Lubov Fominskaja [6]

The one with the fraction in the parenthasees

remember
F=P(r)^t
in decay, r<1
in growth, r>1
and r is positive so we don't have wierd fliping values

answer would be f(x)=4(0.25)^x

2nd one is answer

8 0

4 years ago

Read 2 more answers

What is 3.4 as a fraction

alukav5142 [94]

3 4/10 is my answer

please can i have a brainliest

3 0

3 years ago

Read 2 more answers

What is 1178 divided by what equalls 19

erastova [34]

62 (1178/19) is the answer.

8 0

3 years ago

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

PLEASE HELP!! solve for the value of x. <br> A. x=84<br> B.x=58<br> C.x=7<br> D.x=5

Orlov [11]

The answer is C. x=7

8 0

3 years ago