Question

What is the equation of the following line? (-3, 1) and (0,0)

Answer 1

Answer:

$y = -\frac{1}{3} x$

Step-by-step explanation:

We are given the following two points and we are to find the equation of the line which passes through them:

(-3, 1) and (0,0)

Slope = $\frac{0-1}{0-(-3)} =-\frac{1}{3}$

Substituting the given values and the slope in the standard form of the equation of a line to find the y intercept:

$y=mx+c$

$0=-\frac{1}{3} (0)+c$

$c=0$

So the equation of the line is $y = -\frac{1}{3} x$

Answer 2

Answer:

$y = -\frac{1}{3}x$

Step-by-step explanation:

The equation of a line in the pending intersection is:

$y = mx + b$

Where m is the slope of the line and b is the intercept with the y axis.

If we know two points $(x_1, y_1)$ and $(x_2, y_2)$ then we can find the equation of the line that passes through those points.

$m =\frac{y_2-y_1}{x_2-x_1}$

$b=y_1-mx_1$

In this case the points are  (-3, 1) and (0,0)

Therefore

$m =\frac{0-1}{0-(-3)}$

$m =\frac{-1}{3}$

$b=1-(\frac{-1}{3})(-3)$

$b=0$

Finally the equation is:

$y = -\frac{1}{3}x$