If the entire race is 40 miles, then the second checkpoint is 3/4 of the whole way, which is 30 miles because 40 ÷ 4 = 10 and 10 x 3 = 30. This means that there are 30 miles between the start and the second checkpoint. 2/5 of 30 is 12 because 30 ÷ 5 = 6 and 6 x 2 = 12. Therefore, the answer is 12 miles
Answer:
3/14
Step-by-step explanation:
5/7 minus 1/2 is 5/7 - 1/2
5/7 and 1/2 are both called proper fractions. 5 and 1 in each fraction are called the numerator while 7 and 2 are called denominators
5/7 - 1/2
Step one
Find the lowest common multiple (LCM) of the denominators of each fractions
Multiples of 7
7 x 1 = 7
7 x 2 = 14
7 x 3 = 21
Multiples of 2
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
The lowest common multiple of 2 and 7 is 14
Step 2
The LCM of 2 and 7 becomes the common denominator for both fractions.
14/7 = 2
14/2 = 7
5/7 - 1/2 = [2(5) - 7(1)]/14 = (10 - 7)/14
= 3/14
Answer:
79
Step-by-step explanation:
Add.
17 + 2 = 19
Multiply.
19 x 4 = 79
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
Answer:
<h2>Option A</h2>
Step-by-step explanation:
<h3>To round to ONE decimal place means one significant number should be after the decimal point (.)</h3><h3>Option A is the correct answer because if I a zero leads after the decimal point then it isn't significant.</h3><h3>The zero in option A is insignificant but other numbers are and it says to ONE decimal place so option A is the correct answer.</h3><h3>Hope this helps.</h3>
Good luck ✅.
