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Liono4ka [1.6K]
3 years ago
8

What is the range of the function on the graph (1,2),

Mathematics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

gu is the answer of range of function on graph

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BRAINLIEST FOR WHO EVER GET THIS RIGHT triangle has a leg of 6 yards and a hypotenuse of 8 yards. What is the length of the othe
Alja [10]
Using the Pythagorean theorem a^2 + b^2 = c^2
 where a and b are the legs and c is the hypotenuse
 so a = 6 and c = 8

lets solve for b

6^2 + b^2 = 8^2

36 + b^2 = 64

b^2 = 64 - 36
b^2 = 28

b = sqrt(28)
b = 5.29
b = 5.3 yards



4 0
3 years ago
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The scale of a map is 5 inch = 40 miles. If 2 cities are 15 inches apart on the map, how
galben [10]

Answer:

120 miles from border to border cause if we consider the mile zero then it depends what's the areal of a city

4 0
3 years ago
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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
Y = x + 2<br> y = 3x - 4
exis [7]

Answer:

x=3; y=5

Step-by-step explanation:

y=x+2

y=3x-4

so x+2=3x-4

2x=6

x=3

because y=x+2

                  x=3

so y=3+2

     =5

8 0
3 years ago
1 point
Ber [7]
15
Explanation:
you just divide 90 by 6
6 0
2 years ago
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