From what I'm understanding of these questions, the biggest thing you need to answer these is the formulas for cylinders and triangular prisms. I'm not sure what the quantities are for either question so I'm going to work with made up numbers to give examples for the formulas. For number 2 with the cylinder, let's consider the formula first:
π × r2 × h <em>OR </em>pi (3.14) times radius squared times height
If you have the height and you have pi, all you need to take is the doubled radius (aka multiply it by 2) and plug that back into the formula. For the sake of an example, I'm going to make up the number 2 for the radius and 6 for the height. Here's what that would look like:
r = 2; double it, resulting in 4
pi x 4^2 x 6
3.14 x 16 x 6
= 301.44
Work with the actual numbers you have and you're good to go.
For number 3, reducing something by 1/2 means dividing by 2. Let's consider the formula and then work through another example:
1/2 x b x h x l <em>OR </em> 1/2 times base times height times length
For the sake of an example, I'll use 10 for the height, 15 for the base, and 20 for the length:
h = 10; reduce by 1/2, resulting in 5
1/2 x 15 x 5 x 20
= 750
Plug in your actual quantities, and remember your volume units. Hope this helps!
Answer:
no
Step-by-step explanation:
To determine if (1, 6) is a solution, substitute x = 1, y = 6 into the left side of both equations and if the value obtained equals the right side then it is a solution.
10(1) - 6 = 10 - 6 = 4 ≠ - 6
- 10(1) + 5(6) = - 10 + 30 = 20 ≠ 30
Then (1, 6 ) is not a solution to the system
Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and 
Therefore segment NO is parallel to the segment KL.
