11 = w - 12 solve the equation. What's the solution

A box is in the shape of an equilateral triangular prism. if the box is to be covered with paper on its lateral sides, how many

Zarrin [17]

The total surface area of the triangular prism that has a height of h and the side length of a is given below.

$\rm a(\dfrac{\sqrt3}{2} \ a + 3h)$

<h3>What is a triangular prism?</h3>

A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.

A box is in the shape of an equilateral triangular prism.

If the box is to be covered with paper on its lateral sides.

Let a be the side length of the equilateral triangle and h be the height of the prism.

Then the surface area of the triangular prism will be

Surface area = 2 × area of triangle + 3 × area of the rectangle

The area of the triangle will be

$\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}$

The area of the rectangle will be

$\rm Area \ of \ rectangle = a \ h$

Then the total surface area will be

$\rm Surface\ area = 2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area = a(\dfrac{\sqrt3}{2} \ a + 3h)$

More about the triangular prism link is given below.

brainly.com/question/21308574

7 0

2 years ago

Help please! This is a Calculus AB question!

Lynna [10]

Answer:

½ ln 3

Step-by-step explanation:

∫ sec²x / tan x dx

If u = tan x, then du = sec²x dx.

∫ du / u

ln|u| + C

ln|tan x| + C

Evaluate between π/4 and π/3.

ln|tan(π/3)| + C − (ln|tan(π/4)| + C)

ln|√3| + C − ln|1| − C

ln(√3)

½ ln 3

7 0

3 years ago

Based on historical data, your manager believes that 40% of the company's orders come from first-time customers. A random sample

Vedmedyk [2.9K]

Answer:

$P(0.26 \leq p \leq 0.43)=0.7204-0.0032=0.7172$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The population proportion have the following distribution

$p \sim N(p=0.4,\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.4(1-0.4)}{91}}=0.0514)$