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Tema [17]
3 years ago
14

Explain how you know if a system of equations has one solution, no solutions, or infinitely many solutions. Write your answers (

3) in Complete Sentences.
Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

Written Below.

Step-by-step explanation:

A system of linear equations has one solution when the graphs intersect at a point. A system of linear equations has no solution when the graphs are parallel. A system of linear equations has infinite solutions when the graphs are the exact same line.

(This uses graphing.)

Sidenote: I hope this helps! :)

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If I chose a number uniformly from the integers from 1 to 25, calculate the conditional probability that the number is a multipl
topjm [15]

Answer:

<h2>1/7</h2>

Step-by-step explanation:

If I choose a number from the integers 1 to 25, the total number of integers I can pick is the total outcome which is 25. n(U) = 25

Let the probability that the number chosen at random is a multiple of  6 be P(A) and the probability that the number chosen at random is is larger than 18 be P(B)

P(A) = P(multiple of 6)

P(B) = P(number larger than 18)

A = {6, 12, 18, 24}

B = {19, 20, 21, 22, 23, 24, 25}

The conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is expressed as P(A|B).

P(A|B) = P(A∩B)/P(B)

Since probability = expected outcome/total outcome

A∩B = {24}

n(A∩B) = 1

P(A∩B) = n(A∩B)/n(U)

P(A∩B) = 1/25

Given B = {19, 20, 21, 22, 23, 24, 25}.

n(B) = 7

p(B) = n(B)/n(U)

p(B) = 7/25

Since P(A|B) = P(A∩B)/P(B)

P(A|B) = (1/25)/(7/24)

P(A|B) = 1/25*25/7

P(A|B) = 1/7

<em></em>

<em>Hence the conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is 1/7</em>

7 0
3 years ago
I really need help please
Ahat [919]

Answer:

the first one and the fith one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In science class Abigail Broadway 0.88 kilogram what is the value of the digit in the tenths place
zaharov [31]
0.88......ones (decimal), tenths, hundredths
so 8 is in the tenths place....8/10
7 0
2 years ago
A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta
nalin [4]

Answer:

Option 2 - Approximately 24–36 pounds

Step-by-step explanation:

Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.

To find : What range of weights would 99.7% of the dogs have?

Solution :

The range of 99.7% will lie between the mean ± 3 standard deviations.

We have given,

Mean weight of Eskimo dogs is \mu=30

Standard deviation of Eskimo dogs is \sigma=2

The range of weights would 99.7% of the dogs have,

R=\mu\pm3\sigma

R=30\pm3(2)

R=30\pm6

R=30+6,30-6

R=36,24

Therefore, The range is approximately, 24 - 36 pounds.

So, Option 2 is correct.

5 0
3 years ago
32.17 divided by 7= i need to estimate and quotient
joja [24]
32.17/7 =

about 4.59571428571429

are there any instructions on rounding it to the nearest tenth, hundredths, etc.?
8 0
3 years ago
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