Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
I believe it is corresponding to the value of x in type of situational problem.
8.4 dhndyshshsjsjs yup that’s it’s 778 it indicates
Multiply 0.25 by 2 and you get 0.50
Answer:
52%
Step-by-step explanation:
250 TAB (Team At Bats)
120 TH (Team Hits)
130 TBO [60+50+20] (Team Batted Out)
130/250 = 52% or .52
