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iVinArrow [24]
3 years ago
6

Find the range for the following set of data: 75, 55, 68, 74, 89, 100, 95, 71, 58, 111, 53, 97, 117, 103, 82, 80 a. 63 c. 81 b.

64 d. 83
Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

(C) 64

Step-by-step explanation:

Largest number: 117   Smallest number: 53

117 - 53 = 64

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What is the relationship between sin(90 degrees) and sin(-90 degrees)
Volgvan

Answer:

sin(90\°)=-sin(-90\°)

Step-by-step explanation:

we know that

sin(90\°)=1

sin(-90\°)=-1

therefore

sin(90\°)=-sin(-90\°)

4 0
3 years ago
Please help me with this ​
e-lub [12.9K]

Answer:

7. 5 \frac{5}{8} pizza

8. B

9. 11 \frac{1}{5} inches

10. -12

11. \frac{3}{20}

12. 4

Step-by-step explanation:

7. 3 \frac{1}{2} \\ + 2 \frac{1}{8}

make them mixed fractions: \frac{7}{2} + \frac{17}{8}

get a common denominator by multiplying \frac{7}{2} by 4: \frac{28}{8} + \frac{17}{8}

add the numerators: \frac{45}{8}

simplify the fraction by dividing 45 by 8: 5 \frac{5}{8}

8. 3 x 6 = 18

5 x 6 = 30

7 x 6 = 42

9 x 6 = 54

therefore, y = 6x

9. 5:7 is similar to 8:L

divide 8 by 5: 1 \frac{3}{5}

multiply 7 by 1 \frac{3}{5}: 11 \frac{1}{5}

L = 11 \frac{1}{5} inches

10. 5 - 2x = 29

subtract 5 from each side: -2x = 24

divide each side by -2: x = -12

11. fruit = 15%

15% = 15/100

simplify by dividing by 5: \frac{3}{20}

12. the y-intercept is where the line crosses the y-axis (the vertical one). the line crosses the y-axis at 4.

4 0
3 years ago
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0
2 years ago
Subtract:
pickupchik [31]

Answer: first question answer is 3x^3+6x^2-24x+27

Second question answer=a^2-ab

Step-by-step explanation:

3 0
3 years ago
Express number in standard form 8.023×10^-7
dem82 [27]
0.0000008023..  This is because since its negative I know that the decimal place will move seven times to the left (think of a number line; the negatives are on the left and the positive are on the right).  Therefore you should get 0.0000008023 as this number in standard form because you moved the decimal place seven to the left.
5 0
3 years ago
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