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3 years ago

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Find the range for the following set of data: 75, 55, 68, 74, 89, 100, 95, 71, 58, 111, 53, 97, 117, 103, 82, 80 a. 63 c. 81 b.

64 d. 83

1 answer:

Maksim231197 [3]3 years ago

5 0

Answer:

(C) 64

Step-by-step explanation:

Largest number: 117 Smallest number: 53

117 - 53 = 64

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3 years ago

The real estate term lake frontage refers to the distance along the edge of a piece of property that touches a lake.

storchak [24]

Answer:

Part a) The lake frontage of lot A is $50.9\ yd$

Part b) The lake frontage of lot B is $58.4\ yd$

Part c) The lake frontage of lot C is $64.7\ yd$

Part d) The prices of the other lots, from least to greatest, are $\$286,836.94$ and $\$317,779.96$

Step-by-step explanation:

we know that

If two figures are similar, then the ratios of its corresponding sides is equal

Find the lake frontage (to the nearest tenth) of each lot shown

we have that

$\frac{174}{(48+55+61)}=\frac{A}{48}=\frac{B}{55}=\frac{C}{61}$

$\frac{174}{164}=\frac{A}{48}=\frac{B}{55}=\frac{C}{61}$

step 1

Find the lake frontage of lot A

$\frac{174}{164}=\frac{A}{48}$

$A=174*48/164=50.9\ yd$

step 2

Find the lake frontage of lot B

$\frac{174}{164}=\frac{B}{55}$

$B=174*55/164=58.4\ yd$

step 3

Find the lake frontage of lot C

$\frac{174}{164}=\frac{C}{61}$

$C=174*61/164=64.7\ yd$

step 4

Find the prices of the other lots

we know that the price of the lot A is $\$250,000$ (given problem)

so

by proportion

$\frac{\$250,000}{50.9}=\frac{\$B}{58.4}=\frac{\$C}{64.7}$

<u>Find the price lot B</u>

$\frac{\$250,000}{50.9}=\frac{\$B}{58.4}$

$B=250,000*58.4/50.9=\$286,836.94$

<u>Find the price lot C</u>

$\frac{\$250,000}{50.9}=\frac{\$C}{64.7}$

$C=250,000*64.7/50.9=\$317,779.96$

The prices of the other lots, from least to greatest, are $\$286,836.94$ and $\$317,779.96$

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4 years ago