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slega [8]
3 years ago
11

Y=-5/3x+3 Y=1/3x-3 (3,2)

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

Step-by-step explanation:

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Which best describes the intersection of two lines.
Serga [27]

Answer:

A Point

Step-by-step explanation:

When two line meet they create a point. almost think of it as two roads intersecting with each other

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2 years ago
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Select the correct difference.<br><br> 5d 2 + 4d - 3 less 3d 2 - 2d + 4
katen-ka-za [31]
<span>5d^2 + 4d - 3 - (3d^2 - 2d + 4)
=</span>5d^2 + 4d - 3 - 3d^2 +  2d - 4
= 2d^2 + 6d - 7
5 0
3 years ago
Who else hates homework
AlladinOne [14]

Answer:

samme

Step-by-step explanation:

3 0
3 years ago
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A diamond today cost ten dollars more than twice what it cost last year.The sum of the cost (last year and this year) is $2500.
nadya68 [22]

Answer:

The cost of the diamond last year is x = $ 830

Step-by-step explanation:

Let the cost of diamond last year = x

the cost of diamond present year = y

Given that diamond today cost ten dollars more than twice what it cost last year.

⇒ y = 2 x + 10  ------ (1)

The sum of the cost (last year and this year) is  = $ 2500

⇒ x + y = $ 2500 -------- (2)

Put the value of y in equation (2) from equation (1), we get

⇒ 2 x + 10 + x = $ 2500

⇒ 3 x = 2490

⇒ x = $ 830

& y = 2500 - 830

⇒ y = $ 1670

Therefore the cost of the diamond last year is x = $ 830

6 0
3 years ago
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
kirill [66]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

This is a two tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 2.35

μ2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.8246

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.0746

Since alpha, 0.05 < than the p value, 0.0746, then we would fail to reject the null hypothesis.

3 0
3 years ago
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