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enot [183]
2 years ago
13

Which of the following expressions is 0.00012 written in scientific notation? A. 0.12 × 10^-3 B. 1.2 × 10^-4 C. 12 × 10^-5 D. 1.

2 × 10^4
Mathematics
2 answers:
In-s [12.5K]2 years ago
5 0

Answer:

B. 1.2 x 10^{-4}

Step-by-step explanation:

Scientific notation is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10. For example, 650,000,000 can be written in scientific notation as 6.5 ✕ 10^8.  Or, in this case it's the opposite since we have a negative number. Since it's a decimal it's multiplied by 10 still but the exponent is negative. All we need to do to find what the exponent would be in this case is to count the number of zeros before the "12." There are 4 zeros before the 12. So your exponent would be -4. Now all we need to do is write out "equation" per say.

1.2 x 10^-4

<u>Hope this helps and have a nice day!</u>

____ [38]2 years ago
3 0

Answer:

B

Step-by-step explanation:

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The missing part in the question;

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Also:

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0  -   4                                        -1

5                                                  1

6                                                  17

7                                                  179

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Answer:

Step-by-step explanation:

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Let assume X to represent the numbers of player chooses which are in the Casino-selected-set of 20.

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Then, the probability mass function of a hypergeometric distribution can be defined as:

P(X=k)=\dfrac{(^m_k)(^{N-m}_{n-k})}{(^N_n)}, k =1,2,3 ... n

Now; the probability that i out of  n numbers chosen by the player among 20  can be expressed as:

P(X=k)=\dfrac{(^{20}_k)(^{60}_{n-k})}{(^{80}_n)}, k =1,2,3 ... n

Also; given that ; When the player selects 2 numbers, a payoff (of odds) of $12 won for every $1 bet is made when both numbers are among the 20

So; n= 2; k= 2

Then :

Probability P ( Both number in the set 20)  =\dfrac{(^{20}_2)(^{60}_{2-2})}{(^{80}_2)}

Probability P ( Both number in the set 20) = \dfrac{20*19}{80*79}

Probability P ( Both number in the set 20) =\dfrac{19}{316}

Probability P ( Both number in the set 20) =\dfrac{1}{16.63}

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From the table able ; the expected payoff can be computed as shown in the attached diagram below. Thanks.

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