All categories

3 years ago

What is 1/2 divided by 3

2 answers:

8 0

Pretty simple actually. first make 3 into a fraction, so it would be 3/1. so now, it's 1/2 ÷3/1. now, switch the numerator and denominator of the last fraction to get 1/3. the change the division sing to multiplication and get 1/2×1/3. then multiply the two numerators and denominators and get 1/6. so there's ur answer

Georgia [21]3 years ago

5 0

(1/2) / 3...when dividing with fractions, " flip " what u r dividing by, then multiply

1/2 * 1/3 = 1/6 <==

You might be interested in

What is the unit rate of 162 heartbeats in 60 seconds?

svetoff [14.1K]

162/60 = 2.7 heartbeats per second

4 0

2 years ago

Read 2 more answers

What is the solution to this equation? x-8=15 A)x=13 B)x=17 C)x=7 D) x=23

Blababa [14]

Hi there! :)

Answer:

x=23

*The answer must have a positive sign.*

Step-by-step explanation:

This lesson it's about addition property of equality.

First, you add by 8 from both sides of an equation.

$x-8+8=15+8$

And then, you add by the numbers. Simplify and solve.

$15+8=23$

Final answer: → $x=23$

Hope this helps!

Thanks!

-Charlie

Have a great day!

3 0

3 years ago

What is |-8| ? -16

olga nikolaevna [1]

Answer:

Those little "sticks" are called absolute value.

For example, the absolute value of 2 is 2, and the absolute value of −2 is also 2. The absolute value of a number may be thought of as its distance from zero along real number line.

Thus, it doesn't matter if the number is positive or negative. As it only counts its distance from 0, on the number line.

I hope it helps.

5 0

1 year ago

Read 2 more answers

to cover a rectangular region of her yard penny needs at least 170.5 square feet of sod. the length of the region is 15.5 feet.

pshichka [43]

To cover at least 170.5 sq.ft. the width must be at least 11 feet
W=170.5sq.ft / 15.5 ft = 11ft

7 0

2 years ago

Consider the function f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0

dybincka [34]

I suppose you mean

$f(x)=\cos(x^2)$

Recall that

$\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}$

which converges everywhere. Then by substitution,

$\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}$

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

$f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}$

(starting at $n=1$ because the summand is 0 when $n=0$ )

b. Naturally, the differentiated series represents

$f'(x)=-2x\sin(x^2)$

To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

$-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}$

and from here,

$-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}$

$-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)$

c. This series also converges everywhere. By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}$

The limit is 0, so any choice of $x$ satisfies the convergence condition.

3 0

3 years ago