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AnnyKZ [126]
3 years ago
6

Find the positive difference between the two solutions to the equation

rt%5B3%5D%7B4%20-%20%5Cfrac%7Bx%5E2%7D%7B3%7D%7D%20%3D%20-2%20" id="TexFormula1" title=" \displaystyle\sqrt[3]{4 - \frac{x^2}{3}} = -2 " alt=" \displaystyle\sqrt[3]{4 - \frac{x^2}{3}} = -2 " align="absmiddle" class="latex-formula">.
The answer is NOT 0.
Mathematics
1 answer:
Verizon [17]3 years ago
8 0

\displaystyle\sqrt[3]{4 - \frac{x^2}{3}} = -2 \\\\ 4-\dfrac{x^2}{3}=-8\\\\ 12-x^2=-24\\\\ x^2=36\\\\ x=6 \vee x=-6\\\\ 6-(-6)=6+6=12

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walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
3 years ago
The sum of two consecutive integers is 345. What are the integers? need help with it
horrorfan [7]

Answer:

hi there ☺️

Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 345

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 345

3X + 3 = 345

3X + 3 - 3 = 345 - 3

3X = 342

3X/3 = 342/3

X = 114

Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.

114 + 115 + 116 = 345

We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.

Step-by-step explanation:

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