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3 years ago

Is - 735,200-702 positive or negative

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

Answer:

negative i believe

Step-by-step explanation:

If you are subtracting -735,200 by -702 then yes it is negative but if you are multiplying them then its a positive

Sphinxa [80]3 years ago

5 0

Answer:

negative

Step-by-step explanation:

-735,200 is already a negative number

If subtract 702 from it, it won't change the number to positive.

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Using compatible numbers to find each quotient. 18.2 divided by 11

UNO [17]

It is 166 just do some side math if you can and I think youtline get it ok but that's what I got if someone eles gets somthing eles matey listen to them

5 0

2 years ago

Please help ASAP I have no clue how to do this

Salsk061 [2.6K]

It’s a triangle
s
r t

rs= 2x+10 and st= x-4

the sides are equal so equal them together then solve

2x+10=x-4
+ 4 +4
2x+14=x

you got x alone so x=2x+14

now you plug in 2x+14 in for the x in rs and st

rs= 2(2x+14)+10
4x+28+10
4x+38

st= (2x+14)-4
2x+14-4
2x-10

6 0

3 years ago

Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin

NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

Assuming that $\bar X =5.5$ and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=1086-1=1085$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that $t_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139$

$5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861$

So on this case the 95% confidence interval would be given by (5.139;5.861) We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0

3 years ago

What missing angle of the figure

aniked [119]

Answer:

138

Step-by-step explanation:

152+125=277

277-135=142

around 138

4 0

3 years ago

The hartford insurance company has hired you to poll a sample of adults about their car purchases. what is wrong with using tele

lawyer [7]

Answer:

Step-by-step explanation:

Given that the hartford insurance company has hired you to poll a sample of adults about their car purchases.

Here the insurance company is using convenience sampling to select customers so they resorted to taking the names from telephone directories.

But this may not be reliable since persons owning cars need not have telephones and similarly persons having telephones need not own cars

Owning a car and name appearing in telephone directory need not be associated at all

So taking random sample of names from telephone directories may not give the required accurate result since here sample cannot be assumed to represent the population of car owners.

6 0

3 years ago