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Elina [12.6K]
2 years ago
6

Ways to end Maltreatment towards women

Mathematics
1 answer:
cupoosta [38]2 years ago
5 0
Bring greater attention to violence<span> 
</span> <span>Provide women with access to legal representation
</span>create safe place to discuss gender violence
be supportive
stop victim blaming
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Find the rate of commission to the nearest whole percent if the sale was $5,000 and
tatiyna

Answer:

the answer would be 16%, but if its rounded to nearest whole percent it would be 20

Step-by-step explanation:

6 0
2 years ago
What is the length of ab and bc ? a= (1,-3) b= (3,-1) C= (5,-3)
ddd [48]

Answer:

the length is (1,3

Step-by-step explanation:

the length is 3,1

5 0
3 years ago
Khan academy Find the median of the data in the dot plot below. chocolate chips
Helga [31]

Answer:

Where's the picture?

Step-by-step explanation:

Can't see it.

6 0
3 years ago
Evaluate the piece-defined function for the given of x by matching the domain values with the range values
Elenna [48]

Answer:

The correct answer is:

(1) d

(2) b

(3) a

(4) c

(5) e

Step-by-step explanation:

The given problem is incomplete. Find the attachment of the full question.

According to the question,

(1)

By putting x = -2, we get

f(x)=(-2)^3-5

       =-8-5

       =-13

(2)

By putting x = 0, we get

f(x)=(0)^3-5

       =0-5

       =-5

(3)

By putting x = 3, we get

f(x)=8

(4)

By putting x = 9, we get

f(x)=(2)^{9-7}

       =(2)^2

       =4

(5)

By putting x = 11, we get

f(x)=(2)^{11-7}

       =(2)^4

       =16

7 0
2 years ago
the height of an object thrown vertically is given by s=-16t^2+100t+200. Height is meter and time is n seconds.
koban [17]

Answer:

456.25m

Step-by-step explanation:

Since the question did not ask for what to find, we can as well look for the maximum height reached by the object

Given the height of an object thrown vertically expressed as;

s=-16t^2+100t+200.

At max height,

dS/dt = 0

-32t+100 = 0

-32t = -100

t = 100/32

t = 3.125s

Get the Max height

s(3.125) = -16(3.125)²+100(3.125)+200

s(3.125) = -156.25+312.5+200

s(3.125) = 456.25m

Hence the maximum height reached by the object is 456.25m

5 0
3 years ago
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