A line passes through the point (–2, 7) and has a slope of –5.
2 answers:
Answer:
B
Step-by-step explanation:
Let's create an equation in point-slope form, which is: , where
is the point and m is the slope.
Here, our point is (-2, 7) and our slope is m = -5 so plug these in:
Now, if (a, 2) lies on this line, then it should satisfy the equation. So plug in a for x and 2 for y:
2 - 7 = -5(a + 2)
-5 = -5(a + 2)
Divide by -5:
1 = a + 2
Subtract 2 from both sides:
a = -1
Thus, the answer is B.
Hope this helps!
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First, isolate y on one side to find some information about the graph.
3x+4y=-10
4y=-10-3x
y=(-10-3x)/4
Now find out the x and y intercepts of this equation;
(0)=(-10-3x)/4
4x0=-10-3x
0=-10-3x
3x=-10
x=-10/3 or -3.3333 (x-intercept)
y=(-10-3(0))/4
4y=-10
y=-10/4 or -5/2 = -2.5 (y-intercept)
Plot these points onto your graph and connect the lines.
I have attached a graph below, I'm sorry I couldn't do it on paper.
Hope I helped :)
3x+4y=-10
4y=-10-3x
y=(-10-3x)/4
Now find out the x and y intercepts of this equation;
(0)=(-10-3x)/4
4x0=-10-3x
0=-10-3x
3x=-10
x=-10/3 or -3.3333 (x-intercept)
y=(-10-3(0))/4
4y=-10
y=-10/4 or -5/2 = -2.5 (y-intercept)
Plot these points onto your graph and connect the lines.
I have attached a graph below, I'm sorry I couldn't do it on paper.
Hope I helped :)