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3 years ago

A line passes through the point (–2, 7) and has a slope of –5.

Mathematics

2 answers:

Sati [7]3 years ago

6 0

Answer:

B. -1

Step-by-step explanation:

Slope = (y2 - y1)/(x2 - x1)

-5 = (7 - 2)/(-2 - a)

-5(-2 - a) = 5

10 + 5a = 5

5a = -5

a = -1

ICE Princess25 [194]3 years ago

5 0

Answer:

Step-by-step explanation:

Let's create an equation in point-slope form, which is: $y-y_1=m(x-x_1)$ , where $(x_1,y_1)$ is the point and m is the slope.

Here, our point is (-2, 7) and our slope is m = -5 so plug these in:

$y -7=-5*(x-(-2))$

$y -7=-5*(x+2)$

Now, if (a, 2) lies on this line, then it should satisfy the equation. So plug in a for x and 2 for y:

2 - 7 = -5(a + 2)

-5 = -5(a + 2)

Divide by -5:

1 = a + 2

Subtract 2 from both sides:

a = -1

Thus, the answer is B.

Hope this helps!

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