Straight line adds up to 180
Triangle adds to 180
180-150=30
103+30=133
180-133=47
X=47°
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
X axis : -t1 cos 60 + t2 cos 60 = 0
t2 cos 60 = t1 cos 60 ; t2 = t1
Y axis : t1 sin 60 + t2 sin 60 - 150 = 0
since t2 = t1
2t1 sin 60 = 150
t1 ( sqrt(3)/2) = 150/2
t1 = 50 [sqrt(3)]
t2 = 50 [sqrt(3)]
t3 = 150 N
hope this helps
Ling JM is also 23 centimeters because line LJ and JM are a line but broken into two segments
