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Flauer [41]
3 years ago
7

Rewrite 140 1/8 in radical form

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
140^1/8 =  \sqrt[8]{140} 
julia-pushkina [17]3 years ago
3 0
a \frac{x}{n}=\sqrt[n]{a^x} 140  \frac{1}{8} =   \sqrt[8]{140^1} 140 \frac{1}{8} =  \sqrt[8]{140} 

                                                        

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Mike wrote down a number on a piece of paper and hid it from his friends. He rounded his number to different places and his frie
Naddik [55]

Answer: 145,998, 7,000, and 25,991

My guess :))

Step-by-step explanation:

145,998  7,002  4,506  26,991   12,497

<u>First, Mike rounded his number to the nearest ten</u>

146,000  7,000  4,510   27,000   12,500

<u>Then, he rounded his number to the nearest hundred.</u>

146,000  7,000  4,500  27,000   12,500

<u>Last, he rounded his number to the nearest thousand.</u>

146,000  7,000  5,000  27,000   12,000

3 0
2 years ago
Find the area of a triangle with points (-8,8) , (10,-2), and (-8,-8)
tatuchka [14]

Answer:

144

Step-by-step explanation:

Base:16

Height: 18

Triangle area formula: (bxh)/2

16x18=288

288/2=144

8 0
2 years ago
Triangle angle sum theorem<br> What is the value of z?
prisoha [69]

Answer:

z=3

Step-by-step explanation:

→32+76+24z=180[Sum of all sides of a triangle]

→108+24z=180

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→z=72/24

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7 0
2 years ago
Read 2 more answers
Find the mid point of PQ if P (0,0) and Q (5, 12)
Simora [160]
Using the midpoint formula we get:

(x,y)=(0+5/2, 0+12/2) or (5/2, 6) as the midpoint.
5 0
3 years ago
Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x
Triss [41]

Answer:

\frac{1}{ 2\sqrt{7} }

Step-by-step explanation:

\lim_{x\to 0}  \frac{ \sqrt{x + 7}  -  \sqrt{7} }{x}  \\  \\  = \lim_{x\to 0}  \frac{( \sqrt{x + 7}  -  \sqrt{7}) }{x}  \times  \frac{( \sqrt{x + 7}   +   \sqrt{7}) }{( \sqrt{x + 7}   +  \sqrt{7}) }  \\  \\   = \lim_{x\to 0}  \frac{( \sqrt{x + 7} )^{2}  -  (\sqrt{7})^{2}  }{x( \sqrt{x + 7}   +  \sqrt{7})}  \\  \\   = \lim_{x\to 0}  \frac{( {x + 7}  -  {7}) }{x( \sqrt{x + 7}   +  \sqrt{7})}   \\  \\ = \lim_{x\to 0}  \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7}   +  \sqrt{7})} \\  \\ = \lim_{x\to 0}  \frac{ {1}}{\sqrt{x + 7}   +  \sqrt{7}}  \\  \\  =  \frac{1}{ \sqrt{0 + 7} +  \sqrt{7}  } \\  \\  =  \frac{1}{ \sqrt{7} +  \sqrt{7}  }  \\  \\  =  \frac{1}{ 2\sqrt{7} }

6 0
3 years ago
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