Answer:
1
Step-by-step explanation:
anything raised to the power of 0 would equal 1 and p doesn't equal 1 here.
There are 61 blue marbles
<em><u>Solution:</u></em>
Let "b" be the number of blue marbles
Let "r" be the number of red marbles
Given that bag contains blue marbles and red marbles, 75 in total
number of blue marbles + number of red marbles = 75
b + r = 75 -------- eqn 1
The number of blue marbles is 5 more than 4 times the number of red marbles
number of blue marbles = 5 + 4(number of red marbles)
b = 5 + 4r ------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 4r + r = 75
5 + 5r = 75
5r = 75 - 5
5r = 70
r = 14
From eqn 2,
b = 5 + 4(14) = 5 + 56 = 61
b = 61
Thus there are 61 blue marbles
Answer:
A. |5| < |–8| is the correct option.
Answer:
0.13
Step-by-step explanation:
From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once
we need to select 2 nickels from 5 nickels and select 2 dimes from 8 dimes and 1 quarter from 7 quarters
There are total of 5+8+7=20 coins
select 5 coins from total of 20 coins
2 nickels can be selected from 5 nickels in 5C2 ways

2 dimes selected from 8 dimes

1 quarter selected from 7 quarter

5 coins selected from 20 coins

probability of getting 2 nickels, 2 dimes, and 1 quarter
