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3 years ago

Please help me I snipped my Pic

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

The first A because once you plug in the numbers into the x,y it is easier to find the solution.

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Select the two values of x that are roots of this equation.

alina1380 [7]

C
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3 years ago

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

2 years ago

Can someone help me plz lol I can't figure this one out

lidiya [134]

$4NO+6H_{2} O\Leftrightarrow4 NH _{3}+5O_{2}$

Step-by-step explanation:

$NO+H_{2} O\rightarrow NH _{3}+O_{2}$

$4NO+6H_{2} O\Leftrightarrow4 NH _{3}+5O_{2}$

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3 years ago

SnackTime Foods produced 24,200,000 grams of popcorn last year, which was placed in 11-

likoan [24]

Answer:

2,200,000 :) give brainliest

Step-by-step explanation:

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3 years ago

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Romashka-Z-Leto [24]

$HEY THERE !!!$

It is a function because here in case there is a value of y for x so it is a function.

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3 years ago

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