<h2>Steps</h2>
So for this, we will be creating an equation using the exponential formula - which is 
(a = initial value, b = growth/decay).
Firstly, we know that the original population of the deer is 1,500 so that will be our a value.
Next, we know that the population is growing by 2% annually. With this, we will <em>add</em> 1 and 0.02 (2% in decimal form) since the population is <em>increasing</em>.
1.02 will be our b variable. Now putting it together, our equation is: 
Now that we have our equation set up, plug 4 into the x variable and solve for y as such (Remember to not round until the very end):
<h2>Answer</h2>
<u>After 4 years, the deer population will be 1,624.</u>
Answer:
answer is 0.4
Step-by-step explanation:
2. We have 25+15+10=50 minutes total work out, 25 lifting, so a ratio of
25:50 which is simplified to
Answer: 1:2
3.
7) Area trapezoid = (B+b).H/2, but the Median is equal to (B+b)./ 2
84 =12 . H ==> H = 84/12 ==> H = 7
11) Area Equilateral triangle inscribe in a cercle with Radius R = 2√3
Area = (B.. Altitude) / 2. Calculate H, the altitude. The altitude in an equilateral triangle bisects the opposite side. Apply Pythagoras
(2√3)² = (√3)² + H² ==> 12 = 3 + H² ==> H² = 9 & H = 3
Hence Are = (2√3 x 3) /2 ==> 3√3 unit² or 5.2 unit²
12) Area of regular hexagone with perimeter =12
regular hexagone is formed with 6 equilateral triangles with
each side =12/6 = 2 units
Let's calculate the area of 1 equilateral triangle. Follow the same logic as in problem 11 & you will find that Altitude = √3, Area =(2.√3)/2 =√3 =1.73 Unit³
13) a) Circumference of a circle : 2πR==> 2π(30) =60π = 188.4
b) Area of a circle =πR³ ==> π(30)² = 900π = 2,826 unit²
