Answer: The answer would be 3 & 1
Answer:
7
Step-by-step explanation:
At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless?
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
(-x-1)(x-1)(x^2+6)
distribute from there i think?
math papa website can help with this... im not that good at math
Answer:
no solution
Step-by-step explanation:
6n=6n
