The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
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D)One solution. b=5
Distribute 2 times b plus 2 times 3
2b+6
2b+6+2b=26
Combine like terms 4b+6=26
Subtract 6 from both sides
4b=20
Divide both sides by 4
b=5
Check by substituting 5 for b
2 (5+3)+2(5)=26
2(8) + 2(5)=26
16+10=26
26=26
Answer:
y= -2
Step-by-step explanation:
Please see attached picture for full solution.
(From the 4th to 5th line, I multiplied both sides by 8)
Answer:
at 6pm it was 18 degrees
Step-by-step explanation:
10 pm: -10
9 pm : -3
8 pm: 4
7 pm: 11
6 pm: 18
Add 7
Answer:
This is just multiplying not simplify.