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Grace [21]
3 years ago
11

How do you find the lower quartile and the upper quartile (using a cumulative frequency table)

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

Step-by-step explanation:

take the total frequency from the data given i.e n

for upper quartile you multiply by 3/4 and for lower quartile you multiply by 1/4

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If the tank is then field to capacity how many half-gallon bottles how many cords will it make?
lukranit [14]

Answer:

Divide 12 by 4 first to figure out how many gallons are in each 1/4 of the tank. 

12/4=3

So if I added another 1/4 to the capacity:

It could hold 15 gallons. 

All you have to do to find how many half bottles can be filled is to times 15 by two since we are filling half gallon bottles.

15x2=30

30 bottles.

6 0
3 years ago
Can someone pls help me with this question. Ill give brainliest!!
creativ13 [48]

Answer:

  • Keep plugging in the points and see the ones that work, for example, (-1,7)
  • y=5x+12\\(7)=5(-1)+12\\7=7 true, so select it
  • Keep doing that for the rest of them , some like (3,15) won't work so you just have to keep testing each point.
5 0
2 years ago
Read 2 more answers
Count on and count back by 10 and 100
lianna [129]

1. 461

2. 760

3. 467

4. 795

5. 802

6. 643

7. 228

8. 479

9. 118 stickers (from Alex)

10. 543 (10 more) gives 553. You can find out the number that is 10 more when you add the regular number by 10, 543 + 10 = 553.

Hope this helped!

Nate

6 0
3 years ago
What is the derivative of the following function? f(x) = 4x^6/cos^5(x)
KIM [24]

Answer:

f'(x) = \frac{24x^{5} \cos x + 20x^{6}\sin x}{\cos^{6}x }

Step-by-step explanation:

We have to find the derivative of the following function:

f(x) = \frac{4x^{6} }{\cos^{5} x }

Now, differentiating both sides with respect to x we get,

f'(x) = \frac{\cos^{5}x (24x^{5}) - 4x^{6}(5\cos^{4}x )(- \sin x)}{(\cos^{5}x )^{2}}

⇒ f'(x) = \frac{ 24x^{5} \cos x + 20 x^{6}\sin x}{\cos^{6}x } (Answer)

{Since, we know that, \frac{d(mx^{n} )}{dx} = m \times n x^{(n - 1)} and \frac{d(\cos^{n} x)}{dx} = n \cos^{(n - 1)} x(- \sin x) }

5 0
3 years ago
Given P(x) = 2x3+ 3x2- x + 4, find P(0) and P(-2).
pshichka [43]

9514 1404 393

Answer:

  P(0) = 4

  P(-2) = 2

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

  P(0) = 2·0³ +3·0² -0 +4

  P(0) = 4

__

  P(-2) = 2·(-2)³ +3·(-2)² -(-2) +4 = 2(-8) +3(4) +2 +4

  P(-2) = -16 +12 +2 +4

  P(-2) = 2

6 0
3 years ago
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