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2 years ago

What is the simplified form of i^13

Mathematics

1 answer:

Nikitich [7]2 years ago

4 0

Answer:

Step-by-step explanation:

$\begin{array}{lclcr}i^{1} & = &(\sqrt{-1})^{1}&=& i\\i^{2} & = & (\sqrt{-1})^{2}& =&-1\\i^{3} & = & (\sqrt{-1})^{3}&=&-i\\i^{4} & = & (\sqrt{-1})^{4}& = &1\\\end{array}$

Multiplying by i repeats the pattern .

Thus, any i⁴ⁿ = 1

If n = 3, 4n = 12, so

i¹² = 1 and

i¹³ = i¹ = i

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What is 5.316 - 1.942 (show ur work)

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