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3 years ago

Suppose S is between R and T. Use the Segment Addition Postulate to solve for y.

Mathematics

1 answer:

ehidna [41]3 years ago

8 0

Answer:

Step-by-step explanation:

S is a point on line segment RT.

So RS+ST=RT.

(7y-1)+(y+5)=28

Combine like terms:

8y+4=28

Subtract 4 on both sides:

8y=24

Divide both sides by 8:

y=3

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Use distributive property to simplify <br> -(x+3y-z)

UkoKoshka [18]

Answer:

-x - 3y + z

Step-by-step explanation:

Think of a imaginary 1(-1 because of the sign) in front of the parenthesis and distribute it to the other number and so x will become -x, 3y will become -3y and -z will become z because two negatives make a positive.

4 0

3 years ago

Eliza’s backpack weighs 18 and StartFraction 7 over 9 EndFraction pounds with her math book in it. Without her math book, her ba

kramer

Answer:

about 3.9 lbs

Step-by-step explanation:

18 7/9 lbs - 14 7/8 lbs

convert mixed numbers to improper fractions

169/9 - 119/8

convert to common denominator

1352/72 - 1071/72

subtract numerators

281/72

about 3.9 lbs

4 0

3 years ago

Read 2 more answers

Complete the equation of the line through ( 4 , -8 ) and ( 8 , 5 )

irinina [24]

Answer:

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( 4 ,-8)

point B( x₂ , y₂) ≡ (8 , 5)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

$(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\$

Substituting the given values in a above equation we get

$(y-(-8))=(\frac{5-(8)}{8-4})\times (x-4)\\ \\(y+8)=\frac{13}{4}(x-4)\\\\4(y+8)=13(x-4)\\4y+32=13x-52\\13x-4y=84...............\textrm{which is the required equation of the line AB}$