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Harlamova29_29 [7]
2 years ago
5

How many real solution does the equation x^7+14x^5+16x^3+30x-560=0

Mathematics
1 answer:
White raven [17]2 years ago
7 0
Consider the given equation to be f(x) whose first derivative is positive for all real x. This implies f(x) is a strictly increasing function. Thus it has only 1 root.

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