3 years ago

How many real solution does the equation x^7+14x^5+16x^3+30x-560=0

1 answer:

7 0

Consider the given equation to be f(x) whose first derivative is positive for all real x. This implies f(x) is a strictly increasing function. Thus it has only 1 root.

You might be interested in

Frank wrote these ratios to describe the number of votes each candidate received compared to the total. Which one is wrong, and

strojnjashka [21]

Answer:The right answer is (B)

Step-by-step explanation:

Your welcome

3 0

3 years ago

14. Find the solution of the initial value problem y′′ + y = F(t), y(0) = 0, y′(0) = 0, where F(t) = ⎧⎪⎨⎪⎩ At, 0≤ t ≤ ????, A(2?

Vinvika [58]

Yxgxgggffggyygfccccgyu

3 0

3 years ago

PLEASE HELP ME!!!

Llana [10]

Answer:

Rent

Step-by-step explanation:

Yes

3 0

3 years ago

Read 2 more answers

Solve the equation 4x^2+36=0

raketka [301]

Answer:

it have no answer in real number(but it have in complex number if you know)

Step-by-step explanation:

4x^2+36=0

4x^2=-36

(if you know complex numbers see this: x^2=-9 then

$x = \frac{ + }{} 3i$

)

7 0

3 years ago

HELP ME PLEASE!!!!!!!!

lozanna [386]

Answer:

Step-by-step explanation:

use a proportion

( 3/4 ) / 1 1/8 = ( 4/4) / x teaspoons

x = 1.5

3 0

3 years ago