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Mekhanik [1.2K]
2 years ago
5

Doug took 93 minutes to answer 31 questions. Click on the equation that can be used to determine the number of questions, q, tha

t Doug answered per minute. How many questions did Doug answer per minute?
Mathematics
1 answer:
melisa1 [442]2 years ago
5 0

Answer:

3 questions

Step-by-step explanation:

93/31

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Can someone help me in number 2 <br><br> Will give brainlist
Charra [1.4K]
The center is point C
The line segment that has a radius is CT
A chord is QT
Diameter is RT
8 0
3 years ago
A point is dilated by a scale factor of 1/3 centered about the origin, resulting in the
Andreas93 [3]

Answer:

(-18, 9)

Step-by-step explanation:

If a coordinate A(x,y) is dilated by a factor of k, the new coordinates will be expressed as;

A' = (kx, ky)

A' = A (kx, ky)

Given the following

k = 1/3

A' = (-6, 3)

Substitute

(-6, 3) = 1/3(x, y)

Cross multiply

3(-6, 3) = (x, y)

(x, y) = (3(-6), 3(3))

(x, y) = (-18, 9)

Hence the coordinate prior to dilation is (-18, 9)

5 0
3 years ago
Find the solution of the system of equations.<br><br> -7x-6y=59<br> -8x-6y=58
murzikaleks [220]
So the easiest method for this problem would be elimination. This is what you do...

-7x - 6y = 59
-1( -8x - 6y = 58)
New equations...

-7x - 6y = 59
 8x + 6y = 58    (Add equations)
---------------------
1x = 1
Divide
x = 1
Now find the y value.
-7(1) - 6y = 59
-7 - 6y = 59 
Add 7 to both sides.
-6y = 66
Divide
y = -11
So your solution is ( 1, -11)
I hope this helps love! :)
5 0
3 years ago
Example 3 find the local maximum and minimum values and saddle points of f(x, y) = x4 + y4 − 4xy + 1. solution we first locate t
allsm [11]
f(x,y)=x^4+y^4-4xy+1

\begin{cases}f_x=4x^3-4y\\f_y=4y^3-4x\end{cases}

We have critical points whenever both partial derivatives vanish:

4x^3-4y=0\implies x^3=y\implies x=y^{1/3}
4y^3-4x=0\implies y^3=x=y^{1/3}\implies y^6=y\implies y=0,y=-1,y=1
\begin{cases}y=0\implies x=0\\y=-1\implies x=-1\\y=1\implies x=1\end{cases}

The Hessian is

\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}12x^2&-4\\-4&12y^2\end{bmatrix}
\det\mathbf H(x,y)=(12xy)^2-16

At (0,0), we have \det\mathbf H(0,0)=-16, so (0,0) is a saddle point.

At (-1, -1), we have \det\mathbf H(-1,-1)=128>0 and f_{xx}(-1,-1)=12>0, so (-1, -1) is a local minimum.

At (1, 1), we have \det\mathbf H(1,1)=128>0 and f_{xx}(1,1)=12>0, so (1, 1) is also a local minimum.

3 0
3 years ago
Will give brainliest
Gekata [30.6K]

Answer:

d. y-intercept (0,5); x-intercept (5/2,0)

Step-by-step explanation:

y intercept is when x = 0, then y = 5 or (0,5)

x intercept is when y = 0, then x = 5/2 or (5/2,0)

x    0     1      2     3      4

y    5    3      1      -1      -3

5 0
2 years ago
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