The center is point C
The line segment that has a radius is CT
A chord is QT
Diameter is RT
Answer:
(-18, 9)
Step-by-step explanation:
If a coordinate A(x,y) is dilated by a factor of k, the new coordinates will be expressed as;
A' = (kx, ky)
A' = A (kx, ky)
Given the following
k = 1/3
A' = (-6, 3)
Substitute
(-6, 3) = 1/3(x, y)
Cross multiply
3(-6, 3) = (x, y)
(x, y) = (3(-6), 3(3))
(x, y) = (-18, 9)
Hence the coordinate prior to dilation is (-18, 9)
So the easiest method for this problem would be elimination. This is what you do...
-7x - 6y = 59
-1( -8x - 6y = 58)
New equations...
-7x - 6y = 59
8x + 6y = 58 (Add equations)
---------------------
1x = 1
Divide
x = 1
Now find the y value.
-7(1) - 6y = 59
-7 - 6y = 59
Add 7 to both sides.
-6y = 66
Divide
y = -11
So your solution is ( 1, -11)
I hope this helps love! :)
We have critical points whenever both partial derivatives vanish:
The Hessian is
At (0,0), we have
, so (0,0) is a saddle point.
At (-1, -1), we have
and
, so (-1, -1) is a local minimum.
At (1, 1), we have
and
, so (1, 1) is also a local minimum.
Answer:
d. y-intercept (0,5); x-intercept (5/2,0)
Step-by-step explanation:
y intercept is when x = 0, then y = 5 or (0,5)
x intercept is when y = 0, then x = 5/2 or (5/2,0)
x 0 1 2 3 4
y 5 3 1 -1 -3
