The center is point C 
The line segment that has a radius is CT
A chord is QT 
Diameter is RT
        
             
        
        
        
Answer:
 (-18, 9)
Step-by-step explanation:
If a coordinate A(x,y) is dilated by a factor of k, the new coordinates will be expressed as;
A' = (kx, ky)
A' = A (kx, ky)
Given the following
k = 1/3
A' = (-6, 3)
Substitute
(-6, 3) = 1/3(x, y)
Cross multiply
3(-6, 3) = (x, y)
(x, y) = (3(-6), 3(3))
(x, y) = (-18, 9)
Hence the coordinate prior to dilation is (-18, 9)
 
        
             
        
        
        
So the easiest method for this problem would be elimination. This is what you do...
-7x - 6y = 59
-1( -8x - 6y = 58)
New equations...
-7x - 6y = 59
 8x + 6y = 58    (Add equations)
---------------------
1x = 1
Divide
x = 1
Now find the y value.
-7(1) - 6y = 59
-7 - 6y = 59 
Add 7 to both sides.
-6y = 66
Divide
y = -11
So your solution is ( 1, -11)
I hope this helps love! :)
        
             
        
        
        


We have critical points whenever both partial derivatives vanish:



The Hessian is


At (0,0), we have 

, so (0,0) is a saddle point.
At (-1, -1), we have 

 and 

, so (-1, -1) is a local minimum.
At (1, 1), we have 

 and 

, so (1, 1) is also a local minimum.
 
        
             
        
        
        
Answer:
d. y-intercept (0,5); x-intercept (5/2,0)
Step-by-step explanation:
y intercept is when x = 0, then y = 5 or (0,5)
x intercept is when y = 0, then x = 5/2 or (5/2,0)
x    0     1      2     3      4
y    5    3      1      -1      -3