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r-ruslan [8.4K]
2 years ago
9

Prove the trig identity cosec theta / cot theta + tan theta = cos theta

Mathematics
1 answer:
Agata [3.3K]2 years ago
5 0

See attached images for proof.

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For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
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Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

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3 years ago
What is 2/4 + 4/5 - 7/10 ? Please help
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Make sure they have all common denominators
\frac{2}{4} + \frac{4}{5} - \frac{7}{10}

\frac{2}{4} * \frac{5}{5} = \frac{10}{20}

\frac{4}{5} * \frac{4}{4} = \frac{16}{20}

\frac{7}{10} * \frac{2}{2} = \frac{14}{20}

\frac{10}{20} + \frac{16}{20} - \frac{14}{20}

Add \frac{10}{20} + \frac{16}{20} = \frac{26}{20}
\frac{26}{20} - \frac{14}{20} = \frac{12}{20}

To simplify, you must find the largest common factor which 4
In \frac{12}{20}
12÷4=3 and 20÷4=5

The answer is \frac{3}{5}
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