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Maslowich
3 years ago
8

(4-5y)-(2y-16) find the difference

Mathematics
2 answers:
swat323 years ago
7 0

Answer:

Step-by-step explanation:

4 - 5y - 2y -16

= 5y - 2y - 16 - 4

= 3y - 12

zimovet [89]3 years ago
5 0

Step-by-step explanation:

= 4 - 5y - 2y + 16

= 20 - 7y

....

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Rewrite the rarional exponent as a radical by extending the properties of integer exponents
Nataly_w [17]

Answer: C

Step-by-step explanation:

Simplify the expression to 2^1/4

Now transform the expression using a^m/n = n root a raised to a power of m.

And that's how you get your answer.

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Nick starts with 20 milligrams of a radioactive substance. The amount of the substance decreases by 14 each week for a number of
zlopas [31]

Answer:

Eric's expression is :

20(\frac{1}{4})^w

and Andrea's is :

(1-0.5)^w

In Eric's expression, 20 represents the initial amount of substance with which he has started the experiment. \thinspace \frac{1}{4}\thinspace is the amount of substance left after each time period (in this case, each week).The variable w in this case represents the number of weeks.

Andrea's expression can be written as :

1\cdot (1-0.5)^w

The one outside of parentheses represents the initial amount of the substance. The one inside of parentheses represents 100% of the original amount of the substance. 0.5 represents the 50% of the substance that is lost each time period. The variable w in this case represents the number of weeks.

8 0
3 years ago
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On a coordinate plane, parallelogram R S T U has points (negative 4, 4), (2, 6), (6, 2), and (0, 0). What is the area of paralle
Ad libitum [116K]

Answer:

The area of the parallelogram is;

32 square units

Step-by-step explanation:

The given parameters are;

The coordinates of the parallelogram RSTU = R(-4, 4), S(2, 6), T(6, 2), and U(0, 0)

We note that the area of a parallelogram = Base length × Height

From the drawing of the parallelogram RSTU, we have;

The base length = The length of \overline {TU} = The length of \overline {SR} = √((2 - (-4))² + (6 - 4)²) = 2·√10

The height of a parallelogram is perpendicular to its base length = The line \overline {VT}

∴ Where, the slope of the base length = m, the slope of the height = -1/m

The slope, 'm' of \overline {SR} = (6 - 4)/(2 - (-4)) = 1/3

Therefore, the slope of the height = -1/(1/3) = -3

We note that a point on the height is the point 'T', therefore, the equation of the line in point and slope form is therefore;

y - 0 = -3·(x - 0)

∴ y = -3·x

Therefore, the coordinates of the point 'V' is given by the simultaneous solution of the equations of \overline {SR} and \overline {VT}

The equation of the line \overline {SR} in point and slope form from the point 'R' and the slope 'm = 1/3' is given as follows;

y - 4 = (1/3) × (x - (-4)) = (1/3) × (x + 4)

y = x/3 + 4/3 + 4 = x/3 + 16/3

y = x/3 + 16/3

We then have the coordinate at the point 'V' (x, y) is given as follows;

-3·x = x/3 + 16/3

-9·x = x + 16

-10·x = 16

x = -16/10 = -1.6

x = -1.6

∴ y = -3·x = -3 × -1.6 = -4.8

y = 4.8

The coordinate at the point, V = (-1.6, 4.8)

The length of the line \overline {VT} = The height of the parallelogram = √((-1.6 - 0)² + (4.8 - 0)²) = 8/5·√10

The height of the parallelogram = 8/5·√10

The area of the parallelogram, A = Base length × Height

∴ A = 2·√(10) × 8/5·√(10) = (16/5) × 10 = 32

The area of the parallelogram, A =  32 square units.

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