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3 years ago

13

If r = 25 cm and s = 7 cm, what is the length of t?

1 answer:

Alina [70]3 years ago

8 0

The length would be 15

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Can you help me to solve this

Ber [7]

Answer:

$\frac{4a-2}{2a+1}$

Step-by-step explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

$\frac{8a^2-2}{4a^2+4a+1}$

= $\frac{2(2a-1)(2a+1)}{(2a+1)(2a+1)}$ ← cancel (2a + 1) on numerator/ denominator

= $\frac{2(2a-1)}{2a+1}$

= $\frac{4a-2}{2a+1}$

3 0

3 years ago

Read 2 more answers

Question 4 (1 point)

mrs_skeptik [129]

Answer:

(C)y=0

Step-by-step explanation:

An exponential function of the form $f(x) = a (b^x) + c$ always has a horizontal asymptote at y = c.

Given our function $y=4^x$

Comparing with the form, $f(x) = a (b^x) + c$ , we observe that c=0.

Therefore, the exponential function has an <u>asymptote at y=0.</u>

The correct option is C.

7 0

3 years ago

A square has side length 3 units. What is the length of the diagonal?

ella [17]

9514 1404 393

Answer:

C. 3√2 units

Step-by-step explanation:

The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.

__

If you like, you can see this using the Pythagorean theorem.

d² = s² + s² . . . . . where d is the diagonal, and s is the side

d² = 2s²

d = √(2s²) = s√2

For s=3, ...

d = 3√2

4 0

3 years ago

X-5y=2 and 9x+8=15 solve by substitution

lozanna [386]

$x-5y=2$
Hence $x=2+5y$ (Equation I)
$9x+8=15$ (Equation II)
Substituting Equation I in Equation II
$9(2+5y)+8=15$
$18+45y+8=15$
$26+45y=15$
$45y=-11$
Hence $y= - \frac{11}{45}$

Substituting this in Equation in I to get X

$x-5(- \frac{11}{45} )=2$
$x+ \frac{11}{9}=2$
$x= 2- \frac{11}{9}$
$x= \frac{17}{9}$

7 0

3 years ago

Find the radius r of the sphere.

AleksandrR [38]

Given:

The volume of the sphere = 12348π in³

To find the radius of the sphere.

Formula

The volume of a sphere of radius r is

$V = \frac{4}{3} \pi r^{3}$

According to the problem,

$\frac{4}{3} \pi r^{3} = 12348\pi$

Eliminating π from both the side.

or, $\frac{4}{3} r^{3}= 12348$

or, $r^{3}=\frac{(12348)(3)}{4}$

or, $r^{3}=9641$

or, $r=\sqrt[3]{9261}$

or, $r=21$

Hence,

The radius of the sphere is 21 inches.

3 0

3 years ago

Read 2 more answers