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inessss [21]
3 years ago
7

One way to save time and get to the colleges that you are most interested in at a college fair is to

Computers and Technology
2 answers:
son4ous [18]3 years ago
8 0

Answer:

Identify the location of the college stand in advance.

Explanation:

One way to save time and get to the colleges that you are most interested in at a college fair is to find out in advance the information about the fair, the colleges that are participating and from that pick the more interesting ones and identify the location of their stands. Like that when you arrive to the fair you can go directly to them and find them easily which will save you a lot of time as you won't be walking around the whole place to find them.

mojhsa [17]3 years ago
4 0

Answer: Print out a map of the fair first

Explanation:

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A(n) monitoring vulnerability scanner is one that listens in on the network and determines vulnerable versions of both server an
Tom [10]

Answer: Passive

Explanation: Passive scanning is the process that scans the possibility of the risk that can arise while data is received starting port to the destination. It does the scanning between the server and the client software to define vulnerability .

It cannot work in those network which don't persist the traffic.No false data that is present in the application is detected by it if the data is unclear.

5 0
3 years ago
The following are sources of secondary data except _________. a libraries b data bases c focus groups d syndicated research e sc
sineoko [7]
<span>d syndicated research</span>
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4 years ago
How to set up a paper format in any type of Microsoft version ????
Mashcka [7]
Explain further what you mean by that.
7 0
4 years ago
Boolean logic deals with statements having one of _____ values.
Alexxandr [17]

Answer:

2 values

Explanation:

boolean statements can only be True or False

6 0
3 years ago
The process of finding the largest and smallest numbers is used frequently in computer applications. Write a C++ program that us
WINSTONCH [101]

Answer:

The program to this question can be given as:

Program:

#include<iostream>  //header file

using namespace std;

int main()    //main method

{

int x[10],i,largest = 0,second_largest=0,n;  //variable

cout << "Enter Number of elements :";  //message

cin>>n;

cout << "Insert array elements :";  //message

for(i=0;i<n;i++)  //insert elements in array

{

cin >>x[i];

}

//Finding Largest element  

for(i=0;i<n;i++)

{

if (x[i]>largest)

{

largest = x[i];

}

}

//finding second largset element

for(i=0;i<n;i++)

{

if (x[i]>second_largest)

{

   if(x[i]==largest)

   {

   continue;   //Ignoring largest in order to get second largest

   }

   second_largest=x[i];

}

}

//print value

cout <<"Largest Number:"<<largest<<endl;

cout <<"Second Largest Number:"<<second_largest;

return 0;

}

Output:

Enter Number of elements :5

Insert array elements :33

45

75

87

23

Largest Number:87

Second Largest Number:75

Explanation:

In the above program firstly we define the header file then we define the main method in the main method we define the array and other variables. We first input the number for the size of the array. Then we insert array elements after inserting array elements we search the largest number and the second largest number in the array. To search the largest number in the array we use the loop. To search the first largest number we define a condition that array is greater than the largest number and store the value into the largest variable. Then we check the second largest number in the array for this we use two conditions that are array is greater than the second largest number in this we use another condition that is array is equal to the largest number. If the inner condition is true then it will move forward and end of an inner condition. In the outer condition, the value will be stored on the second_largest variable all the conditions will be done inner the loop. At the last we print values.

3 0
3 years ago
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