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NikAS [45]
3 years ago
12

Solve for B - PLEASE HELP IMMA DIE

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0
First, you would have to add d to both sides to get rid of it
x+d=ab+c/b
Then you would multiply b by both sides to get rid of the b in the denominator
x+d(b)=ab+c
After that, you would subtract c from both sides
x+d(b)-c=ab
Then you would divide both sides by a
x+d(b)-c=b
------------
      a

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Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
What do you call -6 and 6
Oduvanchick [21]
The first one is negative six and the second one is positive six
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3 years ago
Read 2 more answers
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Answer:

yes

Step-by-step explanation:

yes

6 0
3 years ago
I need help Due Tonight !!
Lubov Fominskaja [6]

Answer:

C

Step-by-step explanation:


6 0
3 years ago
In a particular triathlon the athletes cover 1/24 of the total distance by
pav-90 [236]

Answer:

15/8

Step-by-step explanation:

Let "d" be the total distance, that is, the distance for swimming (s), running (r) and going by bike (b).

d = s + r + b   [1]

1/24 of the total distance is covered by  swimming.

s = 1/24 d   [2]

1/3 of the distance is covered by running.

r = 1/3 d  [3]

If we replace [2] and [3] in [1], we get

d = 1/24 d + 1/3 d + b

b = d - 1/24 d - 1/3 d

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The ratio of  the distance covered by bike to the distance covered by running is:

b/r = (5/8 d)/(1/3 d) = 15/8

5 0
3 years ago
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