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3 years ago

Solve for B - PLEASE HELP IMMA DIE

Mathematics

1 answer:

Marta_Voda [28]3 years ago

6 0

First, you would have to add d to both sides to get rid of it
x+d=ab+c/b
Then you would multiply b by both sides to get rid of the b in the denominator
x+d(b)=ab+c
After that, you would subtract c from both sides
x+d(b)-c=ab
Then you would divide both sides by a
x+d(b)-c=b
------------
a

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25/8 as a mixed number

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25/8 = 3 1/8

Result: 25/8 equals to 3 1/8 as a mixed number.

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Allison has 10 coins in dimes and nickels in her purse. The value of the coins is $0.70. Which pair of equations can be used to

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2 years ago

Two companies, A and B, make express delivery for small-item packages in a city. Company A charges a flat fee of RM70 per packag

bazaltina [42]

Using the normal probability distribution and the central limit theorem, it is found that:

a) There is a 0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

b) The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem:

When a fixed constant k multiplies a variable, the mean is $k\mu$ and the standard deviation is $k\sigma$
When two normal variables are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question, b is needed to solve a, so I am going to place the solution to item b first.

Item b:

Flat fee of RM20(not considered for the standard deviation), plus a variable fee of RM3.5, hence:

$\mu_B = 20 + 3.5(9) = 51.5$

$\sigma = 6.1(3.5) = 21.35$

The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

Item a:

This probability is $P(B - A) > 0$ . For the distribution, we have that:

$\mu_{B-A} = \mu_B - \mu_A = 51.5 - 70 = -18.5$

Since A has a constant fee, it's standard deviation is 0, hence:

$\sigma_{B-A} = \sqrt{\sigma_A^2 + \sigma_B^2} = \sqrt{21.35^2} = 21.35$

The probability is 1 subtracted by the p-value of Z when X = 0, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0 + 18.5}{21.35}$

$Z = 0.87$

$Z = 0.87$ has a p-value of 0.8078.

1 - 0.8078 = 0.1922.

0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

A similar problem is given at brainly.com/question/25403659

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2 years ago

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