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3 years ago

How do you find the f(x) inverse using fractions?

1 answer:

4 0

For example.. 1) switch places of x and y. x=3y+1 x=3 y +1
2) try to solve for y. so multiply the denominator by x to get rid of it
3) after multiplying, ur left with xy+x=3 x y + x=3
4) that converts to 2xy= x y =3
5) get rid of 2x on left by placing it on the right
6) convert y to inverse function

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Choose the figures that are polygons

vitfil [10]

Answer:

I'm pretty sure figure A is the only one correct and also figure D

4 0

3 years ago

After a storm damages the community center, Shanika and her friends hold fundraising

Inessa [10]

Answer:

The total amount of money Shanika and her friends want to raise is $2400.

Step-by-step explanation:

Given:

After a storm damages the community center, Shanika and her friends hold fundraising.

After the first event, they raise $240, which is 10% of the total amount that they want to raise.

Now, to find the total amount of money that Shanika and her friends want to raise.

Let the total amount of money that Shanika and her friends want to raise be $x$ .

As given 10% of fundraise is $240.

So, according to question:

$10\%\ of\ x=\$240.$

$\frac{10}{100}\times x=240$

$\frac{10x}{100}=240.$

Multiplying both sides by 100 we get:

$10x=24000.$

Dividing both sides by 10 we get:

$x=\$2400.$

Therefore, the total amount of money Shanika and her friends want to raise is $2400.

3 0

3 years ago

Given: sin(18m-12)=cos(7m+2), find the value of m.

V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

3 0

3 years ago

The dimensions of the tank are 50 cm by 32 cm by 20 cm. The tank is full of water and sand. The ratio of the volume of water to

Sauron [17]

Given:

Dimensions of a tank are 50 cm by 32 cm by 20 cm

The tank is full of water and sand

Ratio of volume of water to the volume of sand is 5:1

To find:

Volume of water in the tank in liters

Solution:

Without loss of generality, let,

Length of tank = 50 cm

Breadth of tank = 32 cm

Height of tank = 20 cm

Then, we have,

Total Volume of the tank = Length * Breadth * Height

$\Rightarrow$ Total Volume = 50*32*20 cc

$\Rightarrow$ Total Volume = 32000 cc

It is given that,

Volume of water : Volume of sand = 5:1

$\Rightarrow$ (Volume of water)/(Volume of sand) = 5/1

Cross multiplying, we have,

Volume of sand = (Volume of water)/5

It is also given that the tank is full of water and sand. This implies that,

Volume of water + Volume of sand = Total Volume

Using the value, we obtained, we get,

Volume of water + (Volume of water)/5 = Total Volume

$\Rightarrow$ (6 * Volume of water)/5 = Total Volume

Plugging in the value of total volume, we get,

$\Rightarrow$ (6 * Volume of water)/5 = 32000 cc

$\Rightarrow$ Volume of water = $\frac{32000*5}{6}$ cc

$\Rightarrow$ Volume of water $\approx$ 26,666.6667 cc

We know that,

1 cc = 0.001 liters

$\Rightarrow$ 26,666.6667 cc = (26666.6667 * 0.001) liters

$\Rightarrow$ 26,666.6667 cc $\approx$ 26.667 liters

Thus, Volume of water in the tank is approximately 26.667 liters

Final Answer:

Volume of water in the tank (in liters) is approximately 26.667 liters

4 0

3 years ago

a supplier sells 2 1/4 pounds of mulch for every 1 1/3 pounds of gravel. The supplier sells 172 pounds of mulch and gravel combi

astraxan [27]

2 1/4=2 3/12 and 1 1/3= 1 4/12

3 0

3 years ago