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3 years ago

What is the GCF OF -20v-50

Mathematics

2 answers:

pantera1 [17]3 years ago

7 0

Answer:

The GCF is -10

Step-by-step explanation:

-10 in the highest/largest number that goes into both -20 and -50.

if you have to factor -20v-50 as well it would be:

-10(2v+5)

and to check if that answer is correct, distribute -10 inside the parenthesses:

-10 times 2v = -20v

-10 times 5 = -50

-20v-50

balandron [24]3 years ago

6 0

$\text{In order to find your GCF, you need to factor}\\\\\text{This means that you need to break down the expression}\\\\\text{The expression is -20v-50}\\\\\text{The GCF ios the factor that all the terms can be simplified by}\\\\\text{In this case, you would see that they oculd be simplified by -10}\\\\\text{Factor out -10:}\\\\-10((2v+5)\\\\\text{This means that the GCF is -10}\\\\\boxed{\text{GCF: -10}}$

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zhuklara [117]

Angle B is the largest angle. , Option D is the correct answer.

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Option D is the correct answer.

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2 years ago

16. A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours

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Answer:

a) 23.11% probability of making exactly four sales.

b) 1.38% probability of making no sales.

c) 16.78% probability of making exactly two sales.

d) The mean number of sales in the two-hour period is 3.6.

Step-by-step explanation:

For each phone call, there are only two possible outcomes. Either a sale is made, or it is not. The probability of a sale being made in a call is independent from other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours, find:

Six calls per hour, 2 hours. So

$n = 2*6 = 12$

Sale on 30% of these calls, so $p = 0.3$

a. The probability of making exactly four sales.

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{12,4}.(0.3)^{4}.(0.7)^{8} = 0.2311$

23.11% probability of making exactly four sales.

b. The probability of making no sales.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138$

1.38% probability of making no sales.

c. The probability of making exactly two sales.

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678$

16.78% probability of making exactly two sales.

d. The mean number of sales in the two-hour period.

The mean of the binomia distribution is

$E(X) = np$

$E(X) = 12*0.3 = 3.6$

The mean number of sales in the two-hour period is 3.6.

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Answer:

Step-by-step explanation:

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hjlf

Answer:

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The table in the attached figure

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