The answer is, <span>A.low pressure, high winds, high precipitation</span>
Interrupt, rupture
contradict, verdict
respect, import
deport, inspect, transport
This is what I got. I hope this helps :)
A) This is predator-prey relationship.
B) Species A is prey and species B is predator.
- If prey population decreases in number, the predator population will also decrease because there is not enough food for predators to survive and vice versa.
- If predator population decreases, the prey population will increase because less prey will be eaten by predators and vice versa.
C) Let population A be Zebras, and population B Lions.
From the graph, at the beginning the there is increase in Lions, as well as in smaller rate in Zebras. At one point, the population of Lions begins to decrease, so they will eat less Zebras. This will allow Zebras to increase population. With more Zebras on the menu, more Lions will eat and increase their chance to survive. This leads to decrease in Zebra population. But again, with less Zebras, the Lion population must decrease allowing Zebra population to increase, and so on.
The rigth answer is the picture 4.
In the case of a hypotonic extracellular medium, there will be a large inflow of water to dilute the Na, thereby increasing the cell volume and there will be an explosion of the membrane in places so hemolysis, the contents of the red cell ( Hemoglobin) is released into the blood plasma.
On the other hand, in the case where the extracellular medium is hypertonic, therefore archi concentrated, well it will be the water of the red cell that will come out without damaging the membrane, we will rather have a red cell that is completely flat and non-functional without release. erythrocyte (Hb) content.
C. The associates proteins are histones
