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Elden [556K]
3 years ago
10

What is 5^4 well it's just multiplying 5 by 5 four times

Mathematics
1 answer:
Olenka [21]3 years ago
5 0
That's right !  So you're on your way to the solution.
Just follow your own suggestion.

           5  x  5  x  5  x  5  =  ?


(If you don't get 625, then go back and check your work.)
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Use the table to write the equation of each quadratic function.
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i d k

Step-by-step explanation:

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3 years ago
Suppose that two small cities have the same longitude, which gives the east-west position of a point on Earth's surface. One has
wel

Answer:

Distance between A and B is 2672 km.

Step-by-step explanation:

Since one city B is having latitude of 23° and other town is having latitude of 47°.Radius of Earth has been given as 6380 km.

Therefore arc A from x-axis will be A = 2πr(∅/360) = 2×3.14×6380×(47/360)

= 5230.90 km

Now arc B from x-axis = 2πr(∅'/360) = 2×3.14×6380(23/360) = 2559.80 km

Therefore distance between them = 5230.9-2559.8 = 2671.9 ≅ 2672 km

Now we will rewrite the arc length formula in radians.

arc A = r×(∅×π/180)

arc A = 6380×(47×π/180) = 1665.9π

arc B = 6380×(23×π/180) = 815.22π    

Now the distance between A and B =  850.68π

6 0
3 years ago
Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that
ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

T: 1 \ R^n \to  1 \ R^n is invertible lines transformation

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T is invertiable linear transformation means that is  

T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix

and \ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists

Let

V \varepsilon\  a\  R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v

so,  

s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \  \forall \ \ v \ \ \varepsilon \ \ 1 R^n

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Given: (↔AB) ║ (↔CD)
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