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Sveta_85 [38]
2 years ago
8

Triangle ABC has side lengths 3, 4, and 5. do the side length s form a Pythagorean triangle?

Mathematics
2 answers:
xz_007 [3.2K]2 years ago
8 0
I believe the term would be a Pythagorean TRIPLE.
and yes 3, 4 and 5 are a Pythagorean Triple,

Over [174]2 years ago
7 0

Answer:  Yes, the side lengths will form a Pythagorean triple.

Step-by-step explanation:  We are given that triangle ABC has side lengths 3, 4 and 5 units.

We are to check whether the side lengths form a Pythagorean triple.

The Pythagorean triple is

<em>Hypotenuse² = Perpendicular² + Base².</em>

Now, for the given triangle ABC, let AB = 3 units, BC = 4 units and CA = 5 units.

Then, we have

AB^2+BC^2=3^2+4^2=9+16=25,\\\\CA^2=5^2=25.

Therefore, we get

CA^2=AB^2+BC^2.

Thus, the side lengths will form a Pythagorean triple with side CA as the hypotenuse.

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Answer:

x < -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

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Equality Properties

Step-by-step explanation:

<u>Step 1: Define Inequality</u>

15 < -5x

<u>Step 2: Solve for </u><em><u>x</u></em>

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  2. Rewrite:                                               x < -3

Here we see that any number <em>x</em> that is smaller than -3 would work as a solution to the inequality.

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3 years ago
What is the value of A when we rewrite... (PLZ HELP QUICK)
Marina86 [1]

Answer:

<h2>\frac{133}{8}</h2>

Step-by-step explanation:

Given,

{( \frac{5}{2} )}^{x}  +  {( \frac{5}{2} )}^{x + 3}

=  {( \frac{5}{2}) }^{x}  +  {( \frac{5}{2}) }^{x}  \times  {( \frac{5}{2} )}^{3}

= ( \frac{5}{2} ) ^{x} (1 +  {( \frac{5}{2} )}^{3}

=  {( \frac{5}{2} )}^{x} (1 +  \frac{125}{8} )

=  {( \frac{5}{2} )}^{x} ( \frac{1 \times 8 + 125}{8} )

=  {( \frac{5}{2}) }^{x} ( \frac{8 + 125}{8} )

{( \frac{5}{2} )}^{x} ( \frac{133}{8} )

Comparing with A • {( \frac{5}{2}) }^{x}

A = \frac{133}{8}

Hope this helps...

Good luck on your assignment...

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