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poizon [28]
2 years ago
13

A biologist is researching a newly discovered species of bacteria. At

Mathematics
1 answer:
lianna [129]2 years ago
6 0

Answer:

  k ≈ 0.1733

Step-by-step explanation:

Using the numbers given, we find the multiplier of the population is 800/200 = 4 in 8 hours. This means the equation of growth can be written ...

  y = 200(4^(t/8))

When this is written in the form ...

  y = 200·e^(kt)

We can compare the two equations to see that ...

  4^(1/8) = e^k

Taking natural logarithms, we have ...

  1/8·ln(4) = k ≈ 0.1733

The growth rate k is approximately 0.1733.

_____

<em>Additional comment</em>

The comparison we were looking for was (4^(1/8))^t = (e^k)^t. Instead of "comparing" the equations, you could set them equal and solve for k.

  200(4^(t/8)) = 200e^(kt)

  4^(t/8) = e^(kt) . . . divide by 200

  t/8·ln(4) = kt·ln(e) . . . . take natural logs

  1/8·ln(4) = k . . . . . . use ln(e) = 1 and divide by t

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