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3 years ago

How do I do this? please help. the second part of the question. i have figured out the first one.

Mathematics

2 answers:

sergeinik [125]3 years ago

8 0

Answer:

Put the wind gauge points two points away from the garden points. Basically for the (2,2) you would make it (4,4) or (3,3) if you wanted to. Or you could do any other side, that's just an easy example.

bearhunter [10]3 years ago

5 0

Answer:

Put the wind gauge points two points away from the garden points.

Step-by-step explanation:

Basically for the (2,2) you would make it (4,4). And then just do that for all the others.

Then you will get your answer.

Hope it helped!

Have a great rest of your day!

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QUICK HOW DO YOU SIMPLIFY THIS EQUATION

Yanka [14]

20.25-9(1/2)+11
=20.25-4.5+11
=26.75

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3 years ago

A+B=44 A+B=44 A:B A:B is equivalent to 4:7. A= B=

ipn [44]

I think is going to be
A=1
B=43
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3 years ago

-1/64, -1/8, -1, -8, ...

Taya2010 [7]

Answer:

I think it's B: an = 8 ⋅ an–1

Step-by-step explanation:

6 0

2 years ago

I need help! Will this would be very appreciated!pls

elena-s [515]

Answer:

No real

solution

Step-by-step explanation:

Firstly, let us check if we would be having a real solution

We start by rewriting the equation

We have this as;

8x^2 -25x + 24 = 0

We proceed to get the discriminant

Mathematically, we have this as;

D = b^2 - 4ac

b is the coefficient of x which is -25

a is the coefficient of x^2 which is 8

c is the last number which is 24

So we have;

D = (-25)^2 - 4(8)(24)

D = 625 - 768 = -143

Since the value of the discriminant is negative, there cannot be real roots

What we have as solution are complex roots

6 0

2 years ago

The volume of a sphere is 972π cubic millimeters. What is the circumference of the great circle of the sphere? (Recall that the

Mashcka [7]

$\boxed{\boxed{\text {Volume =} \dfrac{4}{3} \pi r^3}}$

Given that the volume is 972π mm³, find radius:

$972\pi = \dfrac{4}{3} \pi r^3$

$r^3 = 972\pi \div \dfrac{4}{3} \pi$

$r^3 = 729$

$r = \sqrt[3]{729}$

$r = 9 \text{ mm}$

Find Circumference:

$\boxed { \boxed {\text{Circumference = }2 \pi r}}$

$\text{Circumference = }2 \pi (9)$

$\text{Circumference = }18 \pi \text{ mm}$

8 0

2 years ago

Read 2 more answers

How do I do this? please help. the second part of the question. i have figured out the first one.​

How do I do this? please help. the second part of the question. i have figured out the first one.