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4 years ago

The measure of an angle is 8 degrees less than three times the measure of the angle's supplement. Find the measure of the angle.

Mathematics

1 answer:

Liula [17]4 years ago

4 0

Answer:

262

Step-by-step explanation:

3(90) - 8 = x

270-8 = x

262 = x

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(Using the table provided)

Oliga [24]

The employees represented by the information are employees between under 16 years and adults, and the salaries of these workers

<h3>How to determine the employees the information cover?</h3>

The given parameter is the table of values

From the given table of values, we have the following four columns or fields:

Classification
Weekly
Hourly (full time and part-time)
Casual (includes 20% loading)

Remove the items in brackets

Classification
Weekly
Hourly
Casual

Under the classification column, we have the fields under 16 years to adult.

The other columns represent the salaries of the workers

Hence, the employees represented by the information are employees between under 16 years and adults, and the salaries of these workers

Read more about table of values at:

brainly.com/question/24040786

#SPJ1

3 0

2 years ago

A square garden is surrounded by a walkway of width X. If the area of the garden is 484 ft2 and the area covered by both the gar

slavikrds [6]

The width of the walkway is 3 feet, If the area of the garden is 484 $feet^{2}$ and the area covered by both the garden and the walkway (the entire square) is 784 $feet^{2}$ .

Step-by-step explanation:

The given is,

Area of the garden is 484 $feet^{2}$

Area covered by both the garden and the walkway (the entire square) is 784 $feet^{2}$ .

Let, x - Width of the walkway

Step:1

Formula to calculate area of square is,

$A= a^{2}$ ...........................(1)

Where, r - Radius of square

Step:2

For garden,

A = 484 $feet^{2}$

Equation (1) becomes,

$484=a^{2}$

Take square root on both sides,

$a=\sqrt{484}$

a = 22 feet

For garden and the walkway (the entire square),

A = 784 $feet^{2}$

Equation (1) becomes,

$784=a^{2}$

Take square root on both sides,

$a=\sqrt{784}$

a = 28 feet

Step:3

Ref attachment,

Side of garden and the walkway =

Side of garden + 2 (width of the walkaway)....(1)

28 = 22 + 2 ( x )

2 ( x ) = 28 - 22

= 6

$x = \frac{6}{2}$

Width, x = 3 feet

Result:

The width of the walkway is 3 feet, If the area of the garden is 484 $feet^{2}$ and the area covered by both the garden and the walkway (the entire square) is 784 $feet^{2}$ .