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pav-90 [236]
3 years ago
6

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t

he class, ran 1 mile in 8 minutes. A junior high school class ran 1 mile in an average of 9 minutes, with a standard deviation of 2 minutes. Kenji, a student in the class, ran 1 mile in 8.5 minutes. A high school class ran 1 mile in an average of 7 minutes with a standard deviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes. Who is the fastest runner with respect to his or her class?
Mathematics
1 answer:
EleoNora [17]3 years ago
8 0

Answer:

Rachel

Step-by-step explanation:

We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.  

That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that

mean - x*s = t

For Rachel we have

11 - x*3 = 8, so x = 1.  

Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class

For Kenji we have

9 - x*2 = 8.5, so x = 0.25

Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class

For Nedda we have

7 - x*4 = 8, so x = 0.25

Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.

As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.

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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis
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One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.

TimeA = 2.4h (time of Car A to travel)
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We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.

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We also know that:
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Since both of these equations are equal to x, we can combine them:
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Josh is hiking Glacier National Park. He has now hiked a total of 17 \text{ km}17 km17, start text, space, k, m, end text and is
EastWind [94]

Answer:

The equation to determine the total length in kilometers is  \frac{h}{2} =(17+2)

The total length in kilometers of Josh’s hike is  38 km.

Step-by-step explanation:

Given:

Let the total length in kilometers of Josh’s hike be h.

Now Given that He has now hiked a total of 17 km and is 2 km short of being 1/2 of the way done with his hike.

It means that to reach half of the length of total length Josh needs 2 more km to add in his hiking which is done which is of 17 km.

Framing the above sentence in equation form we get;

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Hence, The equation to determine the total length in kilometers is  \frac{h}{2} =(17+2)

Now Solving the above equation we get;

First we will multiply 2 on both side using Multiplication property we get;

2\times \frac{h}{2}= 2\times(17+2)\\\\h =2\times 19 =38 \ km

Hence,  The total length in kilometers of Josh’s hike is  38 km.

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