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tresset_1 [31]
3 years ago
6

How many sides do 4 hexagons, 1 octagon, and 5 dodecagons have in all?

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0
92 in total because if you add all the sides of all the shapes you get 6*4+1*8+5*10

Vladimir79 [104]3 years ago
5 0
Hexagon = 6 sides = 6 x 4 = 24 

Octagon = 8 sides = 8

Dodecagons = 12 x 5 = 60

24 + 8 + 60 =  92 IN TOTAL 
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Answer:

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Step-by-step explanation:

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kvv77 [185]

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3 0
3 years ago
What is the actual slope of this line?
-BARSIC- [3]

Answer:

  -4

Step-by-step explanation:

The line has a "rise" between the two points of -4 units for a "run" of +1 unit. The slope is the ratio ...

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The slope is -4.

_____

<em>Additional comment</em>

A "whole number" must be non-negative. Here, the slope is negative. If you're restricted to "a fraction or a whole number", then the appropriate answer is the fraction -4/1. We suspect that "integer" is meant where "whole number" is used.

5 0
3 years ago
Write (8a-^3) -2/3 in simplest form
Anna71 [15]

(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

(8a^{-3})^{\frac{-2}{3}

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

(a^m)^n = a^{mn}

Using this, simplify the given expression

(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

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8 0
3 years ago
PLEASE HELP !!!
Art [367]
-3•-4=12, and -3+-4=-7.
this will turn into
(x-3)(x-4)
set them up to equal zero
x-3=0, x-4=0
solve
x=3, x=4
(a)
8 0
3 years ago
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