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3 years ago

How many sides do 4 hexagons, 1 octagon, and 5 dodecagons have in all?

Mathematics

2 answers:

egoroff_w [7]3 years ago

7 0

92 in total because if you add all the sides of all the shapes you get 6*4+1*8+5*10

Vladimir79 [104]3 years ago

5 0

Hexagon = 6 sides = 6 x 4 = 24

Octagon = 8 sides = 8

Dodecagons = 12 x 5 = 60

24 + 8 + 60 = 92 IN TOTAL

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SCORPION-xisa [38]

Answer:

Step-by-step explanation:

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3 years ago

What is the actual slope of this line?

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Answer:

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Step-by-step explanation:

The line has a "rise" between the two points of -4 units for a "run" of +1 unit. The slope is the ratio ...

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_____

Additional comment

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3 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

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8 0

3 years ago

PLEASE HELP !!!

Art [367]

-3•-4=12, and -3+-4=-7.
this will turn into
(x-3)(x-4)
set them up to equal zero
x-3=0, x-4=0
solve
x=3, x=4
(a)

8 0

3 years ago