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tresset_1 [31]
3 years ago
6

How many sides do 4 hexagons, 1 octagon, and 5 dodecagons have in all?

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0
92 in total because if you add all the sides of all the shapes you get 6*4+1*8+5*10

Vladimir79 [104]3 years ago
5 0
Hexagon = 6 sides = 6 x 4 = 24 

Octagon = 8 sides = 8

Dodecagons = 12 x 5 = 60

24 + 8 + 60 =  92 IN TOTAL 
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In triangle ABC , side AB is 6 and side AC is 4: Which statement is needed to prove that segment DE is parallel to segment BC an
Andreyy89

Answer:

Segment AD is 3, and segment AE is 2.

Step-by-step explanation:

In a triangle, the line joining the mid points of two sides is parallel and half of the third sides of the triangle.

Here, ABC is a triangle,

In which,

AB = 6,

AC = 4,

D∈ AB and E∈AC

Let DE ║BC,

And, DE=\frac{1}{2}BC

In triangles ADE and ABC,

\angle ADE\cong \angle ABC  ( Alternative interior angle theorem )

\angle AED\cong \angle ACB

By AA similarity postulate,

\triangle ADE\sim \triangle ABC

∵ Corresponding sides of similar triangle are in same proportion,

\implies \frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}

\frac{AD}{AB}=\frac{AE}{AC}=\frac{BC}{2BC}

\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{2}

\implies AD = \frac{AB}{2}\text{ and }AE =\frac{AC}{2}

\implies AD = \frac{6}{2}=3\text{ and }AE =\frac{4}{2}=2

Hence, the correct option would be,

Segment AD is 3, and segment AE is 2.

4 0
3 years ago
If f(x) = 6(x − 2), find f(5).<br><br> 18<br> 36<br> 108<br> 216
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Answer:

f(5) = 6(5-2) = 18

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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