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2 years ago

How many sides do 4 hexagons, 1 octagon, and 5 dodecagons have in all?

Mathematics

2 answers:

egoroff_w [7]2 years ago

7 0

92 in total because if you add all the sides of all the shapes you get 6*4+1*8+5*10

Vladimir79 [104]2 years ago

5 0

Hexagon = 6 sides = 6 x 4 = 24

Octagon = 8 sides = 8

Dodecagons = 12 x 5 = 60

24 + 8 + 60 = 92 IN TOTAL

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The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

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Which angle(s) is Julian describing?

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I’m sorry I can’t help you, i would need more information

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