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Damm [24]
4 years ago
5

Alexander is blocking off several rooms in a hotel for guests coming to his wedding. The hotel can reserve small rooms that can

hold 3 people, and large rooms that can hold 4 people. Alexander reserved 4 more large rooms than small rooms, which altogether can accommodate 58 guests. Determine the number of small rooms reserved and the number of large rooms reserved.
Mathematics
1 answer:
romanna [79]4 years ago
3 0

Answer:

Small rooms=6

large rooms=10

Step-by-step explanation:

Let the number of small rooms be x

given alexander booked 4 more large rooms than the small rooms.

Therefore the number of large numbers be x+4.

Given each small room can accommodate 3 people.Therefore the total number of people in small rooms are 3x

Given each large room can accommodate 4 people. Therefore the total number of people in large rooms are 4(x+4)

Given total number of people accommodated=58

Total number of guests =number of guests in small rooms + number of guests in large rooms

58=3x+4(x+4)

7x=42

x=6

therefore the number of small rooms =6  and  number of large rooms =10

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Type the correct answer in each box,
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Answer:

The n^{th} sequence aₙ = -15 +5n

The fifth term of the sequence

a₅ = 10

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given sequence

           -10,-5,0,5,10,15,20,.....

The first term = -10

The difference of two terms in the given sequence is equal

d = -5-(-10) = -5 + 10 = 5

d = 0 -(-5) = 5

The given sequence is in arithmetic progression

<u><em>Step(ii):-</em></u>

The n^{th} sequence

a_{n} = a+(n-1) d

aₙ = -10 +(n-1) 5

aₙ = -10 + 5n -5

aₙ = -15 +5n

<u><em>Step(iii):-</em></u>

The n^{th} sequence aₙ = -15 +5n

put n = 5

a₅ = -15 + 5(5) = -15 +25 = 10

<u><em>Final answer:-</em></u>

The n^{th} sequence aₙ = -15 +5n

The fifth term of the sequence

a₅ = 10

<u><em></em></u>

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