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kolbaska11 [484]
3 years ago
7

4.8 yd

Mathematics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

A

Step-by-step explanation:

The composite solid is made up of a cone and a rectangular prism.

Volume of the composite solid = volume of the cone + volume of the rectangular prism

✔️Volume of Cone = ⅓*π*r²*h

Where,

r = 4.8 yd

h = √(6² - 4.8²) = √12.96 = 3.6 yd

Substitute

Volume of cone = ⅓*π*4.8²*3.6

= 86.86 yd²

✔️Volume of rectangular prism = l*b*h

Where,

l = 7 yd

w = 5 yd

h = 4.5 yd

Substitute

Volume of prism = 7*5*4.5 = 157.5 yd²

✔️Volume of composite solid = 86.86 + 157.6 = 244.4 yd² (which is close to 244.36 yd²)

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Lee is sewing vests using 16 green buttons and 40 blue buttons. All the vests are identical, and all have both green and blue bu
faust18 [17]

Answer:

you can make 8 vest

Step-by-step explanation:

2 of them are green and 3 are blue

8 0
3 years ago
Richie and bethany play basketball and practice shooting free throws after school. During one practice session, Richie attempted
mamaluj [8]

Answer:

<em>Bethany did not do better than Richie because her average score was less than his.</em>

Step-by-step explanation:

<u>Average Value</u>

The average or mean value of m successes out of n tries is given by:

\displaystyle \bar x=\frac{m}{n}

During a practice session playing basketball, Richie made m=12 free throws from n=15 attempts. His average score was:

\displaystyle \bar x=\frac{12}{15}=0.8

Bethany made 8 free throws for every 3 that she missed, this means she made 8 out of 11 attempts. Her average score was:

\displaystyle \bar x=\frac{8}{11}=0.72

Bethany did not do better than Richie because her average score was less than his.

5 0
3 years ago
Use prime factorization to find the least common multiple of 54 and 36​
irinina [24]
Answer: 108


Explanation:

GCF(36,54) = 18
LCM(36,54) = ( 36 × 54) / 18
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6 0
3 years ago
Does going to a private university increase the chance that a student will graduate with student loan debt? A national poll by t
Snowcat [4.5K]

Answer:

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

\hat p=0.71 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.69 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:  

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.675)=0.047  

If we compare the p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns  is not significantly higher than 0.69.  

5 0
3 years ago
Working alone, it takes Chelsea 13 hours
Tems11 [23]

Answer:

24 hours

Step-by-step explanation:

hoped this helped

7 0
3 years ago
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