Answer:
is 200 times larger than
Step-by-step explanation:
To compare both values we divide the exponents
6 divide by 3 is 2
for simplify exponents we use exponential property
a^m / a^n = a^(m-n)
is 200 times larger than
Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 316 meters
1 answer:
Short answer: the rectangle is a square, so the length and width are ...
(316 m)/4 = 79 m.
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Let x represent the length of the rectangle. Then the width in meters is 316/2 -x. The area is the product of length and width.
area = x(158 -x)
This is the equation of a parabola that opens downward. It has zeros at x=0 and x=158. The vertex is on the line of symmetry, halfway between the zeros, at x=79.
The length is 79 m.
The width is 158 -79 = 79 m.
(316 m)/4 = 79 m.
_____
Let x represent the length of the rectangle. Then the width in meters is 316/2 -x. The area is the product of length and width.
area = x(158 -x)
This is the equation of a parabola that opens downward. It has zeros at x=0 and x=158. The vertex is on the line of symmetry, halfway between the zeros, at x=79.
The length is 79 m.
The width is 158 -79 = 79 m.
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It is approximately -.4048
H=10^(-pH)
log H = -pH
pH=-logH => so it is affirmed that it is -.40
H=10^(-pH)
log H = -pH
pH=-logH => so it is affirmed that it is -.40
You know that BC is congruent to x so you need to solve for x using the ratio:
So then we need to find BC.
We know:
Therefore BC =8
Then:
So then we need to find BC.
We know:
Therefore BC =8
Then: