Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 316 meters
1 answer:
Short answer: the rectangle is a square, so the length and width are ...
(316 m)/4 = 79 m.
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Let x represent the length of the rectangle. Then the width in meters is 316/2 -x. The area is the product of length and width.
area = x(158 -x)
This is the equation of a parabola that opens downward. It has zeros at x=0 and x=158. The vertex is on the line of symmetry, halfway between the zeros, at x=79.
The length is 79 m.
The width is 158 -79 = 79 m.
(316 m)/4 = 79 m.
_____
Let x represent the length of the rectangle. Then the width in meters is 316/2 -x. The area is the product of length and width.
area = x(158 -x)
This is the equation of a parabola that opens downward. It has zeros at x=0 and x=158. The vertex is on the line of symmetry, halfway between the zeros, at x=79.
The length is 79 m.
The width is 158 -79 = 79 m.
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Answer:
The equation of line is:
Step-by-step explanation:
We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?
The equation of line in slope-intercept form is:
where m is slope and b is y-intercept.
We need to find slope and y-intercept.
Finding Slope
Slope can be found using formula:
We have
Putting values and finding slope
So, we get slope:
Finding y-intercept
Using point (-6,-2) and slope we can find y-intercept
So, we get y-intercept b= 6
Equation of required line
The equation of required line having slope and y-intercept b = 6 is
Now transforming in fully reduced form:
So, the equation of line is: