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ELEN [110]
3 years ago
10

I added pics cause it’s 2 in the morning.. I’m having back pain, thigh pain, cramps EVERYWHERE.. headache and just finished baby

sitting my baby brother.. help a gurl out please ( yes I have been copying and pasting)

Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

<em>Conner's work is correct</em>

Step-by-step explanation:

<u>Operations With Exponents</u>

We need to use the rule to find the product of two or more exponential expressions:

x^m\cdot x^n\cdot x^p = x^{m+n+p}

We need to multiply:

(3^5 6^8)(3^9 6^{10})

Base 3 is treated independently from base 6, so we have two groups of operations:

(3^5 6^8)(3^9 6^{10})=3^{5+9} 6^{8+10}

Adding the exponents:

(3^5 6^8)(3^9 6^{10})=3^{14} 6^{18}

Thus, Conner's work is correct

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In a genetics experiment on​ peas, one sample of offspring contained 376green peas and 150yellow peas. Based on those​ results,
ivanzaharov [21]

Answer:

1a. p0= 0.714

1b The result is not reasonably close to the value of 3/4 that was​ expected

Step-by-step explanation:

1a.Since One sample of offspring contained 376 green peas and 150 yellow peas therefore the probability of getting an offspring pea that is green will be:

Green pea/(Green pea+ Yellow pea)

p0= 376 /(376+150)

p0=376/526

Probability of getting Green pea = 0.714

1b.The result is not reasonably close to the value of 3/4 that was expected.

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3 years ago
Marty drinks 2 cups of water each day. Katie drinks 14 times as much as Marty. How many fluid ounces of water do they drink all
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224 ounces.?
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
3 years ago
Divide -1/6 divided -2/9
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Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator, leaving the negative sign on the numerator, and changing the operation to multiplication. Then the equation becomes

For fraction multiplication, multiply the numerators and then multiply the denominators to get

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 9 and 12 using

5 0
2 years ago
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